From conservation of momentum, the ram force can be calculated similarly to rocket thrust:
F = d(mv)/dt = vdm/dt.
<span>In other words, the force needed to decelerate the wind equals the force that would be needed to produce it.
</span><span> v = 120/3.6 = 33.33 m/s
</span><span> dm/dt = v*area*density
</span> dm/dt = (33.33)*((45)*(75))*(1.3)
dm/dt = <span>
146235.375 </span><span>kg/s
</span><span> F = v^2*area*density
</span> F = (33.33)^2*((45)*(75))*(1.3) = <span>
<span>4874025 </span></span><span>N
</span> This differs by a factor of 2 from Bernoulli's equation, which relates velocity and pressure difference in reference not to a head-on collision of the fluid with a surface but to a fluid moving tangentially to the surface. Also, a typical mass-based drag equation, like Bernoulli's equation, has a coefficient of 1/2; however, it refers to a body moving through a fluid, where the fluid encountered by the body is not stopped relative to the body (i.e., brought up to its speed) like is the case in this problem.
Answer:
maximum possible speed by solving above equation for 7D is

minimum possible value of speed for solving x = 6D is given as

Explanation:
Let the nozzle of the hose be at the origin. Then the nearest part of the rim of the tank is at (, ) = (6, 2) and the furthest part of the rim is at (, ) = (7, 2).
The trajectory of the water can be found as follows:


Now from above two equations we have

now we know that height of the cylinder is 2D so we have

by solving above equation we have

now we know that maximum value of x is 7D
so the maximum possible speed by solving above equation for 7D is

minimum possible value of speed for solving x = 6D is given as

Answer:
Velocity of the passenger = 78.8[km/h]
Explanation:
In order to solve this problem, we must observe the train from a distant point of the train. In this way we can observe that the train moves at 80[km/h] relative to the ground.
In such a way that the passenger moves in a direction contrary to the movement of the train.
![v_{pass}=80-1.2\\ v_{pass}=78.8[km/h]](https://tex.z-dn.net/?f=v_%7Bpass%7D%3D80-1.2%5C%5C%20v_%7Bpass%7D%3D78.8%5Bkm%2Fh%5D)
The Observer located outside the train will see how the passenger moves away at 78.8 [km / h] and not at 80[km/h] which is the speed of the train.
I believe the correct answer is C good luck!
An atom gains one or more electrons and becomes negatively charged, or loses one or more electrons and becomes positively charged.