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2 years ago

Calculate the net ionic equation for SnSO4 + Na2S = SnS + Na2SO4

Chemistry

1 answer:

sladkih [1.3K]2 years ago

5 0

The net ionic equation can be given as Sn²⁺ (aq) + S²⁻ (aq) → SnS (s).

<h3>What is an ionic equation?</h3>

The atoms or molecules on losing or gaining electrons in order to achieve the stable configuration results in the formation of positive or negative charge and are termed as ions.

The ionic equation can be given with the formation of the respective ions of the reactant and the product side.

SnSO₄ (aq) → Sn²⁺ (aq) + SO₄²⁻ (aq)

Na₂S (aq) → 2 Na⁺ (aq) + S²⁻ (aq)

SnS (s) → did not dissociates as form a solid covalent compound

Na₂SO₄ (aq) → 2 Na⁺ (aq) + SO₄²⁻ (aq)

The complete ionic equation can be given as:

Sn²⁺ (aq) + SO₄²⁻ (aq) + 2 Na⁺ (aq) + S²⁻ (aq) → SnS (s) 2 Na⁺ (aq) + SO₄²⁻ (aq)

Eliminating the common ions on the product and the reactant side:

Sn²⁺ (aq) + S²⁻ (aq) → SnS (s)

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Acid rain is closely associated with _______________. select one:

DENIUS [597]

I'm pretty sure its B or C. Sorry, hope this helped some....??

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4 years ago

Under identical conditions, separate samples of O2 and an unknown gas were allowed to effuse through identical membranes simulta

Brut [27]

Answer:

The molar mass of unknown gas is 145.82 g/mol.

Explanation:

Volume of oxygen gas effused under time t = 8.24 mL

Effusion rate of oxygen gas = $R=\frac{8.24 mL}{t}$

Molar mass of oxygen gas = 32 g/mol

Volume of unknown gas effused under time t = 3.86 mL

Effusion rate of unknown gas = $R'=\frac{3.86 mL}{t}$

Molar mass of unknown gas = M

Graham's Law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

$\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}$

$\frac{R}{R'}=\sqrt{\frac{M}{32 g/mol}}$

$\frac{\frac{8.24 mL}{t}}{\frac{3.86 mL}{t}}=\sqrt{\frac{M}{32 g/mol}}$

$M=\frac{32 g/mol\times 8.24 \times 8.24}{3.86\times 3.86}=145.82 g/mol$

4 0

3 years ago

If you needed to make 100 mL of a 0.2 M fruit drink solution from the 1.0 M fruit drink

telo118 [61]

Answer:

We take 20.0 mL of the 1.0 M fruit drink solution and then add 80.0 mL of water to make 100 mL of a 0.2 M fruit drink solution.

Explanation:

Using the rule that: the no. of millimoles of a solution before dilution is equal to the no. of millimoles of the solution after the dilution. (MV) before dilution = (MV) after dilution. M before dilution = 1.0 M, V before dilution = ??? mL. M after dilution = 0.2 M, V after dilution = 100 mL. ∴ V before dilution = (MV) after dilution / M before dilution = (0.2 M)(100 mL) / (1.0 M) = 20.0 mL. So, we take 20.0 mL of the 1.0 M fruit drink solution and then add 80.0 mL of water to make 100 mL of a 0.2 M fruit drink solution

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3 years ago

What volume of carbon dioxide will be produced if 2. 90 moles of iron (fe) is produced?

AlexFokin [52]

The volume of carbon dioxide that will be produced is 191.4 g.

Calculation:

The following is the balanced equation for the given reaction:

Fe₂O₃(s) + 3CO(g) → 2Fe(s) + 3CO₂(g),

It is obvious that when 1.0 mole of Fe2O3 reacts with 3.0 mole of CO, 2.0 mole of Fe and 3.0 mole of CO2 are produced.

Hence by using cross multiplication:

If 2.0 mol of Fe was produced with → 3.0 mol of CO₂, from stoichiometry.

Then how many moles of CO₂ are produced by 2.9 mol of Fe?

To find the answer we have a formula:

∴ The no. of moles of CO₂ produced = (3.0 mol)(2.9 mol)/(2.0 mol) = 4.35 mol.

∴ The mass of CO₂ produced = no. of moles x molar mass = (4.35 mol)(44.0 g/mol) = 191.4 g.

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6 0

2 years ago

Rearrange the following equation and solve for x when the hydrogen ion concentration is 0.01 M. pH=4+logx (Recall that pH=−log[H

bezimeni [28]

Answer:

x = 1 x 10⁻²

Explanation:

Since the pH is the same in both cases, the two expressions for pH can be set equal to each other:

pH = 4 + log(x) = -log[H⁺]

The hydrogen ion concentration ([H⁺]) is 0.01 M, so this value can be substituted in the equation:

4 + log(x) = -log(0.01)

4 + log(x) = 2

log(x) = -2

x = 10⁻²

5 0

3 years ago