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aleksley [76]
3 years ago
8

A hockey puck is set in motion across a frozen pond. if ice friction and air resistance are neglected, the force required to kee

p the puck sliding at constant velocity is
Physics
1 answer:
4vir4ik [10]3 years ago
5 0
Mmm tricky.
Constant velocity means there's no net force acting on the puck!

So if there's no friction or air drag force to slow it down, you don't need any force to keep that puck moving.

Once it's in motion, it stays in motion.
(Mmm isn't that a Law of Newton?)
:D
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Given the vector A with components Ax = 2.00, Ay = 6.00, the vector B with components Bx = 2.00, By = 22.00, and the vector D =
nekit [7.7K]

Answer:

<em>The magnitude of vector d is 16 and the angle with the x-axis is 270°</em>

Explanation:

<u>Operations With Vectors</u>

Given two vectors in rectangular components:

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The difference between the vectors is:

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The magnitude of \vec a is:

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The angle \vec a makes with the horizontal positive direction is:

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The question provides the vectors:

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\vec b=(2,22)

\vec d=\vec a-\vec b

Calculate:

\vec d=(2,6)-(2,22)=(0,-16)

The magnitude of \vec d is:

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The angle is calculated by:

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The division cannot be calculated because the denominator is zero. We need to estimate the correct angle by looking at the components of the vector. Since the x-coordinate is zero and the y-coordinate is negative, the vector points downwards (south), thus the angle must be -90° or 270° if the range goes from 0° to 360°.

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3 years ago
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6 0
3 years ago
Read 2 more answers
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