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aleksley [76]
3 years ago
8

A hockey puck is set in motion across a frozen pond. if ice friction and air resistance are neglected, the force required to kee

p the puck sliding at constant velocity is
Physics
1 answer:
4vir4ik [10]3 years ago
5 0
Mmm tricky.
Constant velocity means there's no net force acting on the puck!

So if there's no friction or air drag force to slow it down, you don't need any force to keep that puck moving.

Once it's in motion, it stays in motion.
(Mmm isn't that a Law of Newton?)
:D
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The machine in the figure is ideal and an effort force of
DENIUS [597]

Answer:

1.5 m

Explanation:

Let the distance from the box to the pivot be c.

Let the distance from the pivot to the effort be y.

From the question given above, the following data were obtained:

Effort force (Fₑ) = 7 N

Force of resistance (Fᵣ) = 14 N

Distance from the box to the pivot (c) = 0.75 m

Distance from the pivot to the effort (y) =?

Clockwise moment = Fₑ × y

Anticlock wise moment = Fᵣ × c

Clockwise moment = Anticlock wise moment

Fₑ × y = Fᵣ × c

7 × y = 14 × 0.75

7 × y = 10.5

Divide both side by 7

y = 10.5 / 7

y = 1.5 m

Therefore, the distance from the pivot to the effort is 1.5 m

5 0
2 years ago
A model rocket is shot directly upward, rises to its maximum height and then returns to its launch position in 10.0 s. Assuming
worty [1.4K]

d. 49.0 m/s

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3 0
3 years ago
Review. As an astronaut, you observe a small planet to be spherical. After landing on the planet, you set off, walking always st
anyanavicka [17]

To find the mass of the planet we will apply the relationship of the given circumference of the planet with the given data and thus find the radius of the planet. From the kinematic equations of motion we will find the gravitational acceleration of the planet, and under the description of this value by Newton's laws the mass of the planet, that is,

The circumference of the planet is,

\phi = 25.1m

Under the mathematical value the radius would be

\phi = 2\pi r

r = \frac{25}{2\pi}

r = 3.9788km

Using second equation of motion

x = \frac{1}{2} at^2

Replacing the values given,

1.4 = \frac{1}{2} a (29.2)^2

Rearranging and solving for 'a' we have,

a = 0.003283m/s^2

Using the value of acceleration due to gravity from Newton's law we have that

a = \frac{GM}{r^2}

Here,

r = Radius of the planet

G = Gravitational Universal constant

M = Mass of the Planet

\frac{(6.67*10^{-11})*M}{(3.9788*10^3)^2} = 0.003283

M = 7.79201*10^{14}kg

Therefore the mass of this planet is 7.79201*10^{14}kg

5 0
3 years ago
Why might a plant that normally grows in one environment not grow well in a different one?
disa [49]
A plant that normally grows in one environment not grow well in a different environment because every flower is different around the certain providing environment.
3 0
3 years ago
The potential difference across a resistor in a particular electric circuit is 420 V. The current through the resistor is 19.0 A
damaskus [11]

Answer: 22.11 ohms

Explanation:

Potential difference(v)=420V

Current(I)=19.0 amp

Resistance(r)=?

r=v/I

r=420/19.0

r=22.11 ohms

7 0
3 years ago
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