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AlladinOne [14]
2 years ago
10

An olympic swimming pool is approximately 88,263 ft3. how many cubic meters (m3) is this? assume there are 3.28 ft in 1 meter.

Physics
1 answer:
TiliK225 [7]2 years ago
3 0

There are 2501.3m³ in 88,263 ft³ the Olympic swimming pool.

<h3>What is geometry?</h3>

Along with arithmetic, geometry is one of the oldest subfields of mathematics. It is concerned with spatial characteristics like the separation between objects, their shape and size, and their relative positions. Geometer is the term used to describe a mathematician who specializes in geometry.

<h3>What exactly does geometry in physics mean?</h3>

The area of mathematics known as geometry is concerned with the characteristics of the surrounding environment as well as the shapes of particular objects and their spatial relationships.

<h3>According to the given information:</h3>

swimming pool is approximately 88,263 ft³

assume there are 3.28 ft in 1 meter.

Now ,

Given that :

3.28ft = 1m

1 ft = 1/(3.28)m

So,

1 ft = (1/3.28)³m³

88,263 ft³ = 88263/(3.28)³

                = 2501.3m³

There are 2501.3m³ in the Olympic swimming pool.

To know more about geometry visit:

brainly.com/question/1578538

#SPJ4

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5 0
3 years ago
A fire truck has a searchlight with a resistance of 60 (ohm) which is placed across a 24-V battery. What is the current in this
Mariulka [41]

Answer: 0.4 Amps

Explanation:

Voltage of battery = 24 Volts

Current I = ?

Resistance of searchlight (R)= 60ohms (Ω is the symbol for ohms)

Then, apply the formula for ohms law

Voltage = Current x resistance

i.e V = I x R

24V = I x 60Ω

I = 24V / 60Ω

I = 0.4 Amps (Amps is the unit of current)

Thus, the current in the circuit is 0.4 Amps

3 0
3 years ago
How far apart would you have to place the poles of a 1. 5 v battery to achieve the same electric field?
Zarrin [17]

To place the poles of a 1. 5 v battery to achieve the same electric field is 1.5×10−2 m

The potential difference is related to the electric field by:

∆V=Ed

where,

∆V is the potential difference

E is the electric field

d is the distance

what is potential difference?

The difference in potential between two points that represents the work involved or the energy released in the transfer of a unit quantity of electricity from one point to the other.

We want to know the distance the detectors have to be placed in order to achieve an electric field of

E=1v/cm=100v/cm

when connected to a battery with potential difference

∆v=1.5v

Solving the equation,we find

d =  \frac{ \:Δv}{e}

=  \frac{1.5v}{100v/m}

= 1.5 \times 10 {}^{ - 2} m

learn more about potential difference from here: brainly.com/question/28166044

#SPJ4

6 0
1 year ago
A hockey puck slides 55.0 m along the length of the rink in just 1.25 s. The slight friction between the puck and the ice provid
topjm [15]

Answer:

44.8 m/s

Explanation:

Use the Initial Speed Formula:

InS = 2(d/t) - Final Speed

InS = 2(55/1,25) - 43.2

InS = 2.44 - 43,2

InS = 88 - 43,2

InS = 44.8 m/s

3 0
2 years ago
Which two possible explanations does the video give for why white light changes into colored light? Color is an impurity added t
Alex777 [14]

Answer:

White light contains seven colors, which are separated by the prism.

White light reacts with chemicals in the air to produce seven colors.

Explanation:

It was first observed by Sir Issac Newton, that when white light is passed through a prism, an elongated, coloured patch of light is obtained on a screen placed behind the prism. The seven colours obtained constitute the spectrum of white light.

In nature, white light is separated into its constituent wavelengths when white light interacts with substances in the atmosphere.

3 0
3 years ago
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