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AlladinOne [14]
1 year ago
10

An olympic swimming pool is approximately 88,263 ft3. how many cubic meters (m3) is this? assume there are 3.28 ft in 1 meter.

Physics
1 answer:
TiliK225 [7]1 year ago
3 0

There are 2501.3m³ in 88,263 ft³ the Olympic swimming pool.

<h3>What is geometry?</h3>

Along with arithmetic, geometry is one of the oldest subfields of mathematics. It is concerned with spatial characteristics like the separation between objects, their shape and size, and their relative positions. Geometer is the term used to describe a mathematician who specializes in geometry.

<h3>What exactly does geometry in physics mean?</h3>

The area of mathematics known as geometry is concerned with the characteristics of the surrounding environment as well as the shapes of particular objects and their spatial relationships.

<h3>According to the given information:</h3>

swimming pool is approximately 88,263 ft³

assume there are 3.28 ft in 1 meter.

Now ,

Given that :

3.28ft = 1m

1 ft = 1/(3.28)m

So,

1 ft = (1/3.28)³m³

88,263 ft³ = 88263/(3.28)³

                = 2501.3m³

There are 2501.3m³ in the Olympic swimming pool.

To know more about geometry visit:

brainly.com/question/1578538

#SPJ4

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IrinaVladis [17]
This is the same question that I just answered.

Have present the definition of acceleration:

         a = Δv / Δt, this is change in velocity per unit of time.

a and v are in bold to mean that they are vectors.

1) a body traveling in a straight line and increasing in speed: CORRECT:

Acceleration is the change in velocity, either magnitude or direction or both. So, a body increasing in speed is accelerated.

2) a body traveling in a straight line and decreasing in speed: CORRECT

A decrease in speed is a change in velocity, so it means acceleration.

3) a body traveling in a straight line at constant speed: FALSE.

That body is not changing either direction or speed so its motion is not accelerated but uniform.

4) a body standing still : FALSE.

That body is not changind either direction or speed.

5) a body traveling at a constant speed and changing direction: CORRECT.

The change in direction means that the body is accelerated. The acceleration due to change in direction is named centripetal acceleration.
6 0
3 years ago
Could you pick up a nail using the curved part of the horseshoe magnet farthest from the poles?
nikitadnepr [17]

Yes

Explanation:

One can pick up a nail using the curved part of the horseshoe magnet farthest from the poles.

A horse shoe magnet has magnetic fields all around it.

  • In the presence of magnetic force fields, any magnetic object will be attracted to it.
  • This is the case with any magnet.
  • A magnet is any object with magnetic fields all around it.
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learn more:

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5 0
3 years ago
Which shows the correct steps in the formation of an ionic bond between these atoms?
Natali5045456 [20]

Answer: D

Explanation: I took the test.

I accidentally posted a comment on it too, sorry about that.

5 0
2 years ago
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A fancart of mass 0.8 kg initially has a velocity of &lt; 0.9, 0, 0 &gt; m/s. Then the fan is turned on, and the air exerts a co
Dmitry [639]

Answer:

<-0.45, 0, 0> kgm/s

Explanation:

The change in momentum would equal to the impulse generated by force F = <-0.3, 0, 0> over time duration of Δt = 1.5 second. The impulse is defined as the product of force F and the duration Δt

\Delta p = F \Delta t = (-0.3) * 1.5 = -0.45 kgm/s

So the change in momentum is <-0.45, 0, 0> kgm/s

6 0
3 years ago
A vector has the components Ax=−31m and Ay=41m. What is the magnitude of this vector? What angle does this vector make with the
Fudgin [204]

Answer:

Magnitude of vector A is  51.4 m

The angle of vector A with positive x-axis is θ= 127.1^o}

Explanation:

Given is  

A_{x}=-31m

A_{y\\=41m

Let A_{x} and A_{y\\ are components of a vector A,

The magnitude of vector A will be:

A=\sqrt{A_{x}^2 +A_{y}^2}

   =  \sqrt{(-31)^{2} +41^2}

A  = 51.4 m

we know

 θ1= tan^{-1} \frac{A_{y}  }{A_{x} }

   = tan^{-1}(-\frac{41}{31}  )

   =-52.9^{o

Vector A is present in 2nd quadrant as x-component of vector A is negative and y-component is positive.

For finding the angle of vector with positive x-axis,

θ=180-52.9

θ= 127.1^o}

6 0
3 years ago
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