What type of cut is mainly done with the radial arm saw?
1 answer:
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Answer:
<em>minimum required diameter of the steel linkage is 3.57 mm</em>
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Explanation:
original length of linkage l = 10 m
force to be transmitted f = 2 kN = 2000 N
extension e = 5 mm= 0.005 m
maximum stress σ = 200 N/mm^2 =
maximum stress allowed on material σ = force/area
imputing values,
200 = 2000/area
area = 2000/() =
m^2
recall that area =
=
=
=
=
m = 3.57 mm
<em>maximum diameter of the steel linkage d = 3.57 mm</em>
Answer:
2543 k
Explanation:
This problem can be resolved by applying the first law of thermodynamics
<u>Determine the adiabatic flame temperature</u> when the furnace is operating at a mass air-fuel ratio of 16 for air preheated to 600 K
attached below is a detailed solution
cp = 1200
