Ask question

Ask question

All categories

3 years ago

12

Describe the steps, tools, and technology needed in detail and

1 answer:

Mumz [18]3 years ago

8 0

Answer:

Mass production methods are based on two general principles: (1) the division and specialization of human labour and (2) the use of tools, machinery, and other equipment, usually automated, in the production of standard, interchangeable parts and products.

Explanation:

Step 1: Product Concept. This is where you begin to flesh out your basic idea. ...

Step 2: Research. ...

Step 3: Product Design Development. ...

Step 4: Research and development of the final design. ...

Step 5: CAD. ...

Step 6: CAM. ...

Step 7: Prototype Testing. ...

Step 8: Manufacturing.

You might be interested in

Use the concept that y = c, −[infinity] < x < [infinity], is a constant function if and only if y' = 0 to determine whethe

attashe74 [19]

Answer:

attached below

Explanation:

5 0

3 years ago

What is the difference between an arch and a dome?

bonufazy [111]

This is an arch, its basically a half circle attach to a rectangle, you could also think of it as an upside down U. A dome is a Sphere with the inside hollowed out.

1 difference is a dome is a 3 dimensional shape while an arch is normally not. Or that a dome is the complete shape with a arch act as it’s diameter.

4 0

2 years ago

The advantage of an interferometer is that

victus00 [196]

It can provide measurements of stars with a higher angular resolution than is possible with conventional telescopes.

5 0

1 year ago

Describe the relationships between load, shear force, and bending moment.

Tatiana [17]

Answer:

the relation between load , shear force and bending moment is

shear force in a beam is calculated by the differentiation of the loading with respect to distance or length of the beam

$V = \dfrac{dw}{dx}$

Bending moment in a beam is define as the change of shear force diagram with respect to the length of the beam.

$M = \dfrac{dV}{dx}$

and where as $M = \dfrac{d^2w}{dx^2}$

where V is the shear force , x is the distance in the beam , M is the bending moment and w is the loading on the beam.

6 0

3 years ago

An aluminum alloy [E = 73 GPa] cylinder (2) is held snugly between a rigid plate and a foundation by two steel bolts (1) [E = 18

V125BC [204]

Answer:

$\sigma_A = 58.43 N/mm^2$

Explanation:

Given data:

length of Steel bolt $L_1 = 335 mm$

Length of aluminium cylinder $L_2 = 275 mm$

Pitch of bolt p = 1mm

Modulus of elasticity of steel E = 215 GPa

Modulus of elasticity of aluminium = 74 GP

Area of bolt $= \frac{\pi}{4} 14^2 = 153.93 mm^2$

Area of cylinder = 2300 mm^2

n =1

By equilibrium

$\sum F_y = 0$

$P_A -2P_S = 0$

$P_A =2P_S$

By the compatibility

$\delta _s + \delta_A = nP$

Displacement in steel is $\delta_s = \frac{P_sL_s}{E_sA_s}$

Displacement in Aluminium is $\delta_A = \frac{P_AL_A}{E_AA_A}$

from compatibility equation we have

$\frac{P_sL_s}{E_sA_s} + \frac{P_AL_A}{E_AA_A} = nP$

$\frac{P_s\times 335}{180\times 10^3\times 153.93} + \frac{P_A\times 275}{73\times 10^3\times 2300} = 1\times 1$

$1.20\times 10^[-5} P_s + 1.44\times 10^{-6}P_A = 1$

substitute $P_A =2P_S$

$1.20\times 10^[-5} P_s + 1.44\times 10^{-6} (2\times P_s) = 1$

$1.488\times 10^{-5} P_s = 1$

$P_s = 67204.30 N$

$P_A = 134,408.60 N$

Stress in Aluminium $\sigma = \frac{P_A}{A_A}$

$= \frac{134,408.60}{2300}$

$\sigma_A = 58.43 N/mm^2$

8 0

3 years ago