Answer:
Check the explanation
Explanation:
Question 1.
The secondary current of 250/5 amps CT when 300 amps(rated current of transmission line ) flow in TL is
(5/250 ) X 300 = 6 amps
Question 2
The correct answer to this second question is yes, when Over current relay coil will operate and relay contacts gets close, if the pickup value( Ip) of relay is set as 6 amps in relay. ( because primary current of TL is 1.2 times of CT primary)
Question 3
Tap Block figure (Fig 1) is not available/uploaded in your question.
Answer:
Check the attached image below
Explanation:
Kindly check the attached image below to get the step by step explanation to the question above.
Answer:
The heat of the arc melts the surface of the base metal and the end of the electrode. The electric arc has a temperature that ranges from 3,000 to 20,000 °C
Explanation:
Welding fumes are complex mixtures of particles and ionized gases.
Answer:
230.51 m
Explanation:
Pb = 695 mmHg
Pt = 675 mmHg
Pb - Pt = 20 mmHg
Calculate dP:
dP = p * g * H = (13600)*(9.81)*(20/1000) = 2668.320 Pa
Calculate Height of building as dP is same for any medium of liquid
dP = p*g*H = 2668.320
H = 2668.32 / (1.18 * 9.81) = 230.51 m