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kkurt [141]
3 years ago
12

A long corridor has a single light bulb and two doors with light switch at each door.

Engineering
1 answer:
Zigmanuir [339]3 years ago
6 0

Answer:

The answer is below

Explanation:

Let A represent the first switch, B represent the second switch and C represent the bulb. Also, let 0 mean  turned off and 1 mean turned on. Since when both switches are  in the same position, the light is off. This can be represented by the following truth table:

A                    B                       C (output)

0                    0                        0

0                    1                          1

1                     0                         1

1                     1                          0

The logic circuit can be represented by:

C = A'B + AB'

The output (bulb) is on if the switches are at different positions; if the switches are at the same position, the output (bulb) is off. This is an XOR gate. The gate is represented in the diagram attached below.

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Someone claims that in fully developed turbulent flow in a tube, the shear stress is a maximum at the tube surface. Is this clai
Alika [10]

Answer:

Yes this claim is correct.

Explanation:

The shear stress at any point is proportional to the velocity gradient at any that point. Since the fluid that is in contact with the pipe wall shall have zero velocity due to no flow boundary condition and if we move small distance away from the wall the velocity will have a non zero value thus a maximum gradient will exist at the surface of the pipe hence correspondingly the shear stresses will also be maximum.

5 0
4 years ago
An AC circuit has a resistor, capacitor and inductor in series with a 120 V, 60 Hz voltage source. The resistance of the resisto
aliina [53]

Answer:

(i) 3.5385 ohm, 3.768 ohm (ii) 39.89 A (III) 4773.857 W (vi) 348 var (vii) 0.9973 (viii) 4.1796°

Explanation:

We have given voltage V =120 volt

Frequency f=60 Hz

Resistance R =3 ohm

Inductance L =0.01 H

Capacitance C =0.00075 farad

(i) reactance of of inductor X_L=\omega L=2\pi fL=2\times 3.14\times 60\times 0.01=3.768ohm

X_C=\frac{1}{\omega C}=\frac{1}{2\times 3.14\times 60\times 0.00075}=3.5385ohm

(ii) Total impedance Z=\sqrt{R^2+(X_L-X_C)^2}=\sqrt{3^2+(3.768-3.5385)^2}=3.008ohm

Current i=\frac{V}{Z}=\frac{120}{3.008}=39.89A

(viii) power factor cos\Phi =\frac{R}{Z}=\frac{3}{3.008}=0.9973

(VII) cos\Phi =0.9973

\Phi =4.1796^{\circ}

So power factor angle is 4.1796°

(iii) Apparent power P=VICOS\Phi =120\times 39.89\times 0.9973=4773.875W

(vi) Reactive power Q=VISIN\Phi =120\times 39.89\times SIN4.17^{\circ}=348var

5 0
3 years ago
Packaging Engineers do all of the following except: a. sample food items b. establish standards and guidelines for the product c
Burka [1]
I think its c. develop tasting plans
5 0
3 years ago
Read 2 more answers
calculate the magnitude of the force acting on the pin at D. Pin C is fixed in DE and bears against the smooth slot in the trian
Olenka [21]

Answer:

hello your question lacks the required diagram attached below is the diagram

answer : 58.47 N

Explanation:

The magnitude of the force acting on the Pin D

Fd = \sqrt{Dx^2 + Dy^2}

    = \sqrt{16.80^2 + 56^2}

    = 58.465 N

Dx = 16.80 N

Dy = 56 N

hello attached below is the detailed solution

8 0
3 years ago
The equilibrium fraction of lattice sites that are vacant in silver (Ag) at 700°C is 2 × 10-6. Calculate the number of vacancies
True [87]

Answer:

1.16*10^{23} vacancies/m^3

Explanation:

Data given

temperature =700c

Density=10.35g/cm^3

but

\frac{N_v}{N}=2*10^{-6}\\N_v=2*10^{-6}N\\

Nv is the number of vacant site and N is the number of lattice site.

Since the number of lattice site can also b computed as

N=\frac{p_{Ag} * N_A}{A_{AG}} \\N=\frac{6.022*10^{23} * 10.35*10^6g/m}{107.87g/mol} \\N=5.78*10^{28}atom/m^3

if we substitute the value of the number of lattice into the first equation, we arrive at

N_v=2*10^{-6} *5.78*10^28\\N_v=1.16*10^{23} vacancies/m^3

4 0
4 years ago
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