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melamori03 [73]
3 years ago
13

Consider the following list. list = {24, 20, 10, 75, 70, 18, 60, 35} Suppose that list is sorted using the insertion sort algori

thm as discussed in the book. What is the resulting list after two passes of the sorting phase; that is, after three iterations of the for loop?a. list = {10, 18, 20, 24, 75, 70, 60, 35}b. list = {10, 20, 24, 75, 70, 18, 60, 35}c. list = {10, 18, 20, 24, 35, 70, 60, 75}d. list = {10, 20, 20, 18, 35, 70, 60, 75}
Engineering
1 answer:
Greeley [361]3 years ago
8 0

Answer:

Option B

10,20,24,75,70,18,60,35

Explanation:

The first, second and third iteration of the loop will be as follows

insertion sort iteration 1: 20,24,10,75,70,18,60,35

insertion sort iteration 2:10,20,24,75,70,18,60,35

insertion sort iteration 3: 10,20,24,75,70,18,60,35

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What are cars manufactured with today that allows for quick stopping without the brakes locking up?
stiks02 [169]

Answer:

ABS

Explanation:

an Anti Lock Breaking system will not lock up your breaks even when used in a tight situation. This helps inexperienced drivers with no breaking technique break proprly.

5 0
3 years ago
A 600 MW coal-fired power plant has an overall thermal efficiency of 38%. It is burning coal that has a heating value of 12,000
velikii [3]

Answer:

See step by step explanations for answer.

Explanation:

600 megawatts =

568 690.272 btu / second

thermal eficiency=work done/Heat supllied

0.38=568690.272/Heat supplied

Heat supplied=1496553.35btu /s

heat emmitted to the atmosphere=heat supplied -work done=(1496553.35-568690.272)=927863.1 btu/s

feed rate=(1496553.35)/12000=124.71 lb/s =10775184.1056 lb/day=5 387.472 ton / day

sulphur content released=(0.03*124.71)/(1.496553)=2.5 lb SO2/million Btu of heat input

so

the degree (%) of sulfur dioxide control needed to meet an emission standard=(2.5/0.15)*100=1666.67 %

the CO2 emission rate=220*(1.496553) =329.241 lb/s =12 903.0802 metric ton / day

5 0
3 years ago
The simply supported beam in the Figure has a rectangular cross-section 150 mm wide and 240 mm high.
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Same question idea but different values... I hope I helped you... Don't forget to put a heart mark

4 0
3 years ago
The clepsydra, or water clock, was a device that the ancient Egyptians, Greeks, Romans, and Chinese used to measure the passage
Nookie1986 [14]

Suppose a tank is made of glass and has the shape of a right-circular cylinder of radius 1 ft. Assume that h(0) = 2 ft corresponds to water filled to the top of the tank, a hole in the bottom is circular with radius in., g = 32 ft/s2, and c = 0.6. Use the differential equation in Problem 12 to find the height h(t) of the water.

Answer:

Height of the water = √(128)/147456 ft

Explanation:

Given

Radius, r = 1 ft

Height, h = 2 ft

Radius of hole = 1/32in

Acceleration of gravity, g = 32ft/s²

c = 0.6

Area of the hold = πr²

A = π(1/32)² ---- Convert to feet

A = π(1/32 * 1/12)²

A = π/147456 ft²

Area of water = πr²

A = π 1²

A = π

The differential equation is;

dh/dt = -A1/A2 √2gh where A1 = Area of the hole and A2 = Area of water

A1 = π/147456, A2 = π

dh/dt = (π/147456)/π √(2*32*2)

dh/dt = 1/147456 * √128

dh/dt = √128/147456 ft

Height of the water = √(128)/147456 ft

3 0
4 years ago
Explain why the following scenario fails to meet the definition of a project description.
s344n2d4d5 [400]

Answer:

The youth hockey training facility

Explanation:

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3 years ago
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