The modulus of elasticity is 28.6 X 10³ ksi
<u>Explanation:</u>
Given -
Length, l = 5in
Force, P = 8000lb
Area, A = 0.7in²
δ = 0.002in
Modulus of elasticity, E = ?
We know,
Modulus of elasticity, E = σ / ε
Where,
σ is normal stress
ε is normal strain
Normal stress can be calculated as:
σ = P/A
Where,
P is the force applied
A is the area of cross-section
By plugging in the values, we get
σ = 
σ = 11.43ksi
To calculate the normal strain we use the formula,
ε = δ / L
By plugging in the values we get,
ε = 
ε = 0.0004 in/in
Therefore, modulus of elasticity would be:

Thus, modulus of elasticity is 28.6 X 10³ ksi
Mass and chemical composition
Answer:
Compute the number of gold atoms per cubic centimeter = 9.052 x 10^21 atoms/cm3
Explanation:
The step by step and appropriate substitution is as shown in the attachment.
From number of moles = Concentration x volume
number of moles = number of particles/ Avogadro's number
Volume = mass/density, the appropriate derivation to get the number of moles of atoms
Using the knowledge of computational language in python it is possible to write a code that writes a list and defines the arrange.
<h3>Writing code in python:</h3>
<em>def isSorted(lyst):</em>
<em>if len(lyst) >= 0 and len(lyst) < 2:</em>
<em>return True</em>
<em>else:</em>
<em>for i in range(len(lyst)-1):</em>
<em>if lyst[i] > lyst[i+1]:</em>
<em>return False</em>
<em>return True</em>
<em>def main():</em>
<em>lyst = []</em>
<em>print(isSorted(lyst))</em>
<em>lyst = [1]</em>
<em>print(isSorted(lyst))</em>
<em>lyst = list(range(10))</em>
<em>print(isSorted(lyst))</em>
<em>lyst[9] = 3</em>
<em>print(isSorted(lyst))</em>
<em>main()</em>
See more about python at brainly.com/question/18502436
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All of the above. Answer.