Answer:
The specific heat of zinc is 0.375 J/g°C
Explanation:
<u>Step 1:</u> Data given
Mass of zinc = 19.6 grams
Mass of water = 82.9 grams
Initial temperature of zinc = 98.37 °C
Initial temperature of water = 24.16 °C
Final temperature of water (and zinc) = 25.70 °C
Specific heat of water = 4.184 J/g°C
<u>Step 2:</u> Calculate Specific heat of zinc
Heat lost by zinc = heat won by water
Q=m*c*ΔT
Qzinc = -Qwater
m(zinc)*C(zinc)*ΔT(zinc) = -m(water)*C(water)*ΔT(water)
⇒ with mass of zinc = 19.6 grams
⇒ with C(zinc) = TO BE DETERMINED
⇒ with ΔT(zinc) = T2 -T1 = 25.70 - 98.37 = -72.67°C
⇒ with mass of water = 82.9 grams
⇒ with C(water) = 4.184 J/g°C
⇒ with ΔT(water) = T2 - T1 = 25.70 - 24.16 = 1.54
Qzinc = -Qwater
19.6g* C(zinc) * (-72.67°C) = - 82.9g* 4.184 J/g°C * 1.54 °C
-1424.332*C(zinc) = -534.155
C(zinc) = 0.375 J/g°C
The specific heat of zinc is 0.375 J/g°C
