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Iteru [2.4K]
3 years ago
9

How many molecules are there in 3 moles of aluminum chloride ?

Chemistry
1 answer:
Svetradugi [14.3K]3 years ago
6 0

there are 4 atoms in aluminum chloride

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Instruction
valkas [14]

Answer:

A: object 1

B: object 2

C: object 1

D: object 1

Explanation:

4 0
3 years ago
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How many grams of sodium bicarbonate are needed to completely react with a 0.892 m phosphoric acid solution that contains to 45.
SVETLANKA909090 [29]

Answer:

umm idk if I was right or not

7 0
4 years ago
A family leaves for summer vacation by driving on the highway. The car's tires start the trip with a pressure of 3.8atm at a tem
goldenfox [79]

Answer: The pressure of the tires after driving is 4.9atm

Explanation: Please see the attachments below

4 0
3 years ago
If the specific heat capacity of copper is 387 J/kg/°C, then how much energy is needed to raise the temperature of 400 g of copp
eduard

Answer:

Explanation:

mass = 400 grams * [1 kg/1000 grams] = 0.400 kg

c = 387 Joules / (oC * kg)

Δt = 55 - 30 = 25 oC

E = m*c * Δt

E = 0.4 * 387 * 25

E = 3870 Joules

5 0
3 years ago
Consider the following hypothetical aqueous reaction. A flask is charged with .065 mol of A in a total volume of 100.0 mL. The f
Inga [223]

Answer: 0.422 M⁻¹s⁻¹

Explanation: <u>Reaction</u> <u>Rate</u> is the speed of decomposition of the reactant(s) per unit of time.

A <u>Rate</u> <u>Law</u> relates concentration of reactants, rate reaction and rate constant:

r=k[A]^{x}[B]^{y}

where

[A] and [B] are reactants concentration

x and y are reaction order, not related to the stoichiometric coefficients

k is rate constant

r is rate

Before calculating rate constant, first we have to determine reaction order.

In this question, the reactio order is 2. So, the rate law for it is

-\frac{d[A]}{dt} =k[A]^{2}

and the integrated formula is

\frac{1}{[A]} =\frac{1}{[A]_{0}} +kt

in which

[A]₀ is initial concentration of reactant

Then, using initial concentration at initial time and final concentration at final time:

\frac{1}{0.031} =\frac{1}{0.065} +k(40)

40k=\frac{1}{0.031}-\frac{1}{0.065}

40k=32.26-15.38

k = 0.422

The rate constant for the reaction is 0.422 M⁻¹.s⁻¹

3 0
3 years ago
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