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2 years ago

Which of the following will have the longest-term impact on organisms in a ecosystem?

Chemistry

1 answer:

bearhunter [10]2 years ago

8 0

Answer:

D. Global warming

Explanation:

Hope this Helps.

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The following reaction does not proceed to form a product: H2O + Au---> no reaction. Why is that?. . A. Gold has a higher act

Tresset [83]

I think the correct answer from the choices listed above is option B. The following reaction does not proceed to form a product: H2O + Au---> no reaction because gold has a lower activity than hydrogen and cannot replace it. Hope this answers the question.

3 0

3 years ago

Which one has the highest Hydrogen Bonding:<br> 1. HF<br> 2. HCL<br> 3. H2O<br> 4. NH3

sleet_krkn [62]

Answer:

the answer is the

first one

5 0

3 years ago

Read 2 more answers

What happens when a penny is dropped from a height of 20 meters?

pshichka [43]

Also option C is correct. Hope it helps.

7 0

2 years ago

Calculate the mass of a substance with a density of 1.98 g/mL and a volume of 265 mL.

Vinvika [58]

Answer:

Explanation:

The density of a substance can be found by using the formula

$Density = \frac{mass}{volume}$

Making mass the subject we have

<h3>mass = Density × volume</h3>

From the question

Density = 1.98 g/mL

volume = 265 mL

Substitute the values into the above formula and solve for the mass

That's

mass = 1.98 × 265

We have the final answer as

Hope this helps you

8 0

3 years ago

A Cu2+ solution is prepared by dissolving a 0.4749 g piece of copper wire in acid. The solution is then passed through a Walden

Luda [366]

Answer:

Concentration of $Cr_2O_7^{2-}$ = 0.03101 M

Concentration of $MnO_4^-$ = 0.03721 M

Explanation:

The reduction for $Cr_2O_7^{2-}$ is;

$Cr_2O_7^{2-} + 14 H ^+ _{(aq)} + 6 e^- -----> 2 Cr^{3+} _{(aq)}+7H_2O _{(l)}$

$Cu^+_{(aq)} -----> Cu^{2+} _{(aq)} + 1 e^-$

6 moles of $Cu ^+$ = 1 mole of $Cr_2O_7^{2-}$

number of moles of Cu reacted = $\frac{mass \ of \ Cu \ wire }{ molecular weigh tof \ Cu wire }$

number of moles of Cu reacted = $\frac{0.4749}{63.55}$

number of moles of Cu reacted = 0.00747 mole

number of moles of $Cr_2O_7^{2-}$ reacted = $\frac{0.00747}{6}$

number of moles of $Cr_2O_7^{2-}$ reacted = 0.001245 mole

Concentration of $Cr_2O_7^{2-}$ = $\frac{number \ of moles }{Volume}$

Given that the volume = 40.15 mL = $40.15 *10^{-3}$ ; we have:

Concentration of $Cr_2O_7^{2-}$ = $\frac{0.001245}{40.15*10^{-3}}$

Concentration of $Cr_2O_7^{2-}$ = 0.03101 M

The reduction for $MnO_4^-$ is;

$MnO_4^- + 8H^+ + 5 e^- -----> Mn^{2+} + 4H_2O$

$Cu^+_{(aq)} -----> Cu^{2+} _{(aq)} + 1 e^-$

5 moles of $Cu ^+$ = 1 mole of $Cr_2O_7^{2-}$

number of moles of Cu reacted = $\frac{mass \ of \ Cu \ wire }{ molecular weigh tof \ Cu wire }$

number of moles of Cu reacted = $\frac{0.4749}{63.55}$

number of moles of Cu reacted = 0.00747 mole

number of moles of $MnO_4^-$ reacted = $\frac{0.00747}{5}$

number of moles of $MnO_4^-$ reacted = 0.001494 mole

Concentration of $MnO_4^-$ = $\frac{number \ of moles }{Volume}$

Given that the volume = 40.15 mL = $40.15 *10^{-3}$ ; we have:

Concentration of $MnO_4^-$ = $\frac{0.001494 }{40.15*10^{-3}}$

Concentration of $MnO_4^-$ = 0.03721 M

3 0

3 years ago