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Talja [164]
3 years ago
7

Write a balanced equation for the following:

Chemistry
1 answer:
anygoal [31]3 years ago
7 0
1) P4 + 5O2 = 2P2O5

2) C3H8 + 5O2 = 3CO2 + 4H2O

3) Ca2Si + 4Cl2 = 2CaCl2 + SiCl4
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How many grams are in 1 mole of Ar?
Ilia_Sergeevich [38]

Answer: 39.948 grams

Explanation:

The SI base unit for amount of substance is the mole. 1 mole is equal to 1 moles Ar, or 39.948 grams

3 0
3 years ago
Reaction B could produce a substance with a pH of...<br><br> 14.<br><br> 4.<br><br> 10.<br><br> 7.
scoundrel [369]

Answer:

Explanation:

14: Sodium Hydroxide

4: lemon juice.

10: milk of magnesia ; The great Salt Lake

7: pure water

4 0
3 years ago
Read 2 more answers
Read the information about the three atoms given in the table. Which of them are isotopes of each other?
skelet666 [1.2K]
<span>The option A is correct answer. The isotopes are X and Y. The isotopes are those which have same atomic number but different mass number. Since atomic number has same number of protons or electrons. Thus, isotopes have same number of protons or electrons. Therefore, X and Y are isotopes.</span>
4 0
4 years ago
Read 2 more answers
Is cyclopentane an isomer of pentane? Explain.
Georgia [21]
Cyclopentane is NOT an isomer of pentane.

Isomers must have the same molecular formula.

The molecular formula of pentane is C₅H₁₂, while the molecular formula of cyclopentane is C₅H₁₀.

The two molecules cannot be isomers.
8 0
4 years ago
A chemical reaction takes place inside a flask submerged in a water bath. The water bath contains 8.10kg of water at 33.9 degree
victus00 [196]

Explanation:

The given data is as follows.

        q = 69.0 kJ = 69000 J (as 1 kJ = 1000 J),

       mass (m) = 8.10 kg = 8100 g  (as 1 kg = 1000 g)

        T_{i} = 33.9^{o}C = (33.9 + 273) K = 306.9 K

         C = 4.18 J/gK

As we know that the relation between heat and change in temperature is as follows.

                   q = m \times C \times \Delta T

Putting the values into the above formula to calculate the final temperature as follows.

                  q = m \times C \times \Delta T

       69000 J = 8100 g \times 4.18 J/g K \times (T_{f} - 306.9 K)                

           69000 J = 33858 \times (T_{f} - 306.9 K)

                  (T_{f} - 306.9 K) = 2.037 K

                    T_{f} = (2.037 + 306.9) K

                                  = 308.9 K

or,                               = 309 K (approx)

Thus, we can conclude that the new temperature of the water bath is 309 K.

5 0
3 years ago
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