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riadik2000 [5.3K]

1 year ago

15

another way, speed is a scalar value, while reloolg isa Which ONE of the following represents a toy car that moves at a higher a

verage speed? (12) Show your calculations. A: A toy car that travels 1,50 km in 3 min B: A toy car that travels 800 m in 1,50 min C: A toy car that travels 250 km in 8 hours CAR A: CAR B: CAR C:

1 answer:

erica [24]1 year ago

4 0

Car A will have highest speed is 83.3m/s .

<h3>What is speed ? </h3>

The rate of change of position of an object in any direction.

The S.I unit is m/s . Speed is a scalar quantity it defines only magnitude not direction

.

speed = distance /time

In case of Car A ,

We have given distance 150Km in 3 min ,

First we have convert the distance km to m

150×1000m

then conversion of min to sec

38×60sec

speed = 15000/180

speed = 83.3m/sec

In case of Car B

we have given 800m in 150 min

lets convert the time into second

150×60

Speed = 800/150×60

speed = 0.88m/ s

In case of Car C

We have given here distance 250 Km and time in 8 hours

convert km to m

25000

and time into sec

88×60×60

speed = 0.86m/ s

Hence ,Car A has highest speed amongst them .

To learn more about speed click here

brainly.com/question/7359669

#SPJ9

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Answer:

Part a)

A = 0.0581 m

Part b)

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Explanation:

Slice is dropped on the plate from height 0.250 m

so the speed of the slice while it hit the plate is given as

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here we know that

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$M = 0.400 kg$

from the above equation we have

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$x_1 = 0.01962 m$

now when slice is placed on the plate then the new mean position will be given as

$(0.300 + 0.400)9.81 = 200 x_2$

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now we know that speed of SHM is given as

$v = \omega\sqrt{A^2 - x^2}$

here we have

$\omega = \sqrt{\frac{k}{m + M}}$

$\omega = \sqrt{\frac{200}{0.300 + 0.400}}$

$\omega = 16.9 rad/s$

$a = x_2 - x_1 = 0.0343 - 0.01962 = 0.0147 m$

now from above formula

$0.95 = 16.9\sqrt{A^2 - 0.0147^2}$

$A = 0.0581 m$

Part b)

Time period of scale is given as

$T = \frac{2\pi}{\omega}$

$T = \frac{2\pi}{16.9}$

$T = 0.37 s$

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