Answer:
25 m/s
Explanation:
Given that:
Initial speed, u = 4 m/s
Final velocity, V = 11 m/s
Time, t = 8 seconds
t2, = 16 seconds
Acceleration, a= (change in velocity) / time interval
a = (11 - 4) / 8
a = 7 / 8 = 0.875m/s²
Final velocity, v2 ;
Acceleration * t2
0.875 * 16 = 14
V2 = 14 m/s
Final speed : v + v2 = (11 + 14)m/s = 25m/s
Explanation:
We have,
Surface area, 
The current varies wrt time t as :

(a) At t = 2 seconds, electrical charge is given by :

(b) Current is given by :

Instantaneous current at t = 1 s is,

(c) Current is, 
Current density is given by electric current per unit area.

Therefore, it is the required explanation.
Answer:
5.522 m
Explanation:
Data provided:
Mass, m = 1.03 kg
spring constant, k = 861.1 N/m
Distance by which the spring is compressed, x = 0.36
Thus,
the energy stored in the spring = 
on substituting the values, we get
the energy stored in the spring = 
now,
by the conservation of energy, we have
Potential energy gained by the mass = Energy gained by the spring
or
mgh = 
where,
g is the acceleration due to the gravity
h is the maximum height reached by the mass before falling
on substituting the values in the above relation, we get
1.03 × 9.81 × h = 
or
h = 5.522 m
Answer:
1.8 x 10⁻³⁴ m.
Explanation:
de Broglie wavelength ( λ ) of a moving particle is given by the following expression
λ = h / momentum of the particle
In other words, de Broglie wavelength depends upon the momentum of the particle.
In the given case , particle A which is stationary collides with another particle B having some momentum . After the collision , they move together.No external force acts on them . Therefore after the collision , their momentum will be conserved. In other words , their momentum remains the same as earlier. So their de Broglie wave length will also be the same as earlier , since it depends on the momentum of the moving body.
Hence the de Broglie wavelength of the object will be 1.8 x 10⁻³⁴ m.
Answer:
The value is 
Explanation:
From the question we are told that
The potential of the proton is 
Generally the momentum of the particle is mathematically represented as

Here e is the charge on the proton with value

m is the mass of the proton with value 
So

=> 
So the de-Broglie wavelength isis mathematically represented as

Here h is the Planck's constant with value

=> 
=>