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user100 [1]
4 years ago
12

A large truck collides head-on with a small car. The car is severely damaged as a result of the collision. According to Newton's

third law, how do the forces acting between the truck and car compare during the collision
Physics
1 answer:
Blizzard [7]4 years ago
5 0

Answer: Force on the truck is equal to force on the car.

Explanation: According to the Newton's third law of motion which states that; For every action, there is an equal and opposite reaction. These pair of forces are regarded as action - reaction forces. These size or magnitude of the forces on the colliding objects are equal or the same, while the direction of the colliding objects are opposite.

In the scenario above, both truck and carry have the same mass, however, the damage suffered by the car is based on its smaller mass which makes it unable to withstand the acceleration resulting from the collision.

ma = m(-a)

m= mass, a= acceleration

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. Energy can neither be created nor be destroyed, but it can be changed from one form to another", this law is known as kinetic
Fynjy0 [20]

Answer:

The law of conservation of energy

3 0
3 years ago
In case of collision of objects in two dimensions which statement is true after the collision?
Grace [21]

The correct answer to the question is : C) The horizontal momentum and the vertical momentum are both conserved. 

EXPLANATION :

Before coming into any conclusion, first we have to understand the law of conservation of momentum.

As per the law of conservation of momentum, the total linear as well as angular momentum of an isolated system is always conserved . The law of conservation of energy is a universal fact.

Hence, during any type of collision, the total momentum is always conserved.

Hence, the total horizontal momentum as well as total vertical momentum are always conserved during both elastic as well as inelastic collision.



5 0
3 years ago
Read 2 more answers
A dogs tail hit a 1.3kg flower vase, knocking it over. the net force on the flower vase over time is shown below
lesantik [10]

Answer: 0.15 m/s

Explanation:

​

​

8 0
3 years ago
A mass of .1539 kg moves down a 5 meter ramp in 2 seconds. What
enot [183]

Answer:

Velocity=2.5m/s

KE=4809.375J

Explanation:

Velocity=5m/2s=2.5m/s

KE=½×1539kg×(2.5m/s)²

KE=4809.375J

4 0
3 years ago
A car is stopped for a traffic signal. When the light turns green, the car accelerates, increasing its speed from 0 to 5.40 m/s
tekilochka [14]

Answer:

a) 378Ns

b) 477.27N

Explanation:

Impulse is the defined as the product of the applied force and time taken. This is expressed according to the formula

I = Ft = m(v-u)

m is the mass = 70kg

v is the final velocity = 5.4m/s

u is the initial velocity = 0m/s

Get the impulse

I = m(v-u)

I = 70(5.4-0)

I = 70(5.4)

I = 378Ns

b) Average total force is expressed as

F = ma (Newton's second law)

F = m(v-u)/t

F = 378/0.792

F = 477.27N

Hence the average total force experienced by a 70.0-kg passenger in the car during the time the car accelerates is 477.27N

3 0
3 years ago
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