Question

At what distance from a 27 mw point source of electromagnetic waves is the electric field amplitude 0. 060 v/m ?

Answer 1

The distance from a 27 mw point source of electromagnetic waves where the electric field amplitude 0. 060 v/m will be 21.21 m .

Electromagnetic waves or EM waves are waves that are created as a result of vibrations between an electric field and a magnetic field. In other words, EM waves are composed of oscillating magnetic and electric fields.

The highest point of a wave is known as 'crest' , whereas the lowest point is known as 'trough'. Electromagnetic waves can be split into a range of frequencies. This is known as the electromagnetic spectrum.

c = 3 * $10^{8}$ m/s

∈ = 8.85 * $10^{- 12}$ $C^{2}$ / N/ $m^{2}$

E = 0. 060 v/m

I = P / 4π$r^{2}$

Also , I = c ∈ $E^{2}$ /2

$r^{2}$ = P / 4π I                                 equation 1

substituting the value of I in equation 1

$r^{2}$ = 2 P / 4π (c ∈ $E^{2}$ )

$r^{2}$ = 2 * 27 * $10^{-3}$ / 4 * 3.14 * 3 * $10^{8}$ * 8.85 * $10^{- 12}$  * $(0.06)^{2}$

r = 21.21 m

To learn more about Electromagnetic waves  here

brainly.com/question/12392559

#SPJ4