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KonstantinChe [14]
1 year ago
12

At what distance from a 27 mw point source of electromagnetic waves is the electric field amplitude 0. 060 v/m ?

Physics
1 answer:
n200080 [17]1 year ago
5 0

The distance from a 27 mw point source of electromagnetic waves where the electric field amplitude 0. 060 v/m will be 21.21 m .

Electromagnetic waves or EM waves are waves that are created as a result of vibrations between an electric field and a magnetic field. In other words, EM waves are composed of oscillating magnetic and electric fields.

The highest point of a wave is known as 'crest' , whereas the lowest point is known as 'trough'. Electromagnetic waves can be split into a range of frequencies. This is known as the electromagnetic spectrum.

c = 3 * 10^{8} m/s

∈ = 8.85 * 10^{- 12} C^{2} / N/ m^{2}

E = 0. 060 v/m

I = P / 4πr^{2}

Also , I = c ∈ E^{2} /2

r^{2} = P / 4π I                                 equation 1

substituting the value of I in equation 1

r^{2} = 2 P / 4π (c ∈ E^{2} )

r^{2} = 2 * 27 * 10^{-3} / 4 * 3.14 * 3 * 10^{8} * 8.85 * 10^{- 12}  * (0.06)^{2}

r = 21.21 m

To learn more about Electromagnetic waves  here

brainly.com/question/12392559

#SPJ4

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