Answer:
output work is not possible to have more than 294 kJ value so this is not reasonable claim
Explanation:
As we know that the efficiency of heat engine is given as
now we will have
now we know that efficiency is defined as
So output work is not possible to have more than 294 kJ value
The factors which are affected will be based on the distance or range between the charged objects A and B
<u>Explanation:</u>
<u>Definition:</u>
- The force, F among the two-point size charges A and B are divided by a range r is given by Coulomb formula.
F=9x10^9 AB/r²
<u>Factors:</u>
- If the range among them is doubled the force will be decreased to 1/4 of the initial value. And if the range is split, the force will be four times.
- If the range among them is tripled, the force will be decreased to 1/9 of the initial value. If the range is decreased to one-third of the new value, the force will rise to Nine times the initial value.
Answer: The wavelength changes by a factor of
Explanation:
The equation of the speed of a wave is:
Where:
is the speed, that remains unchanged
is the wavelength
is the frequency
Isolating we have:
Now, if we increase the frequency by a factor of 2:
This means the wavelength changes by a factor of
Answer:
The box will be moving at 0.45m/s. The solution to this problem requires the knowledge and application of newtons second law of motion and the knowledge of linear motion. The vertical component of the force Fp acts vertically upwards against the directio of motion. This causes a constant upward force of 23sin45° to act on the box. Fhe frictional force of 13N also acts vertically upwards and so two forces act upwards against rhe force of gravity resulting un a net force of 0.7N acting kn the box. This corresponds to an acceleration of 0.225m/s². So in w.0s after i start to push v = 0.45m/s.
Explanation: