Multiply 25 times 6, to get 60 seconds and that is your beats per minute. In this case it is 150 BPM.
Answer:
<em>The rebound speed of the mass 2m is v/2</em>
Explanation:
I will designate the two masses as body A and body B.
mass of body A = m
mass of body B = 2m
velocity of body A = v
velocity of body B = -v since they both move in opposite direction
final speed of mass A = 2v
final speed of body B = ?
The equation of conservation of momentum for this system is
mv - 2mv = -2mv + x
where x is the final momentum of the mass B
x = mv - 2mv + 2mv
x = mv
to get the speed, we divide the momentum by the mass of mass B
x/2m = v = mv/2m
speed of mass B = <em>v/2</em>
Answer:
The time period of the rope waves is seconds
Explanation:
The period of a wave, T is equal to 1 divided by the frequency of the wave
The number of waves produced per second by the wave = 7 waves
Therefore;
The frequency of the wave, f = 7 complete cycles per second = 7 Hz
f = 7 Hz
The time period of the rope waves, T = seconds
Passenger
r = 96 km/hr
t = t - 2
Freight
r = 64
t = t You have to solve for t before you can solve for d
The distance is the same for both trains.
Formula
r_passenger_train * time_passenger = r_freight_train * time_freight
Solve
96 km/hr * (t - 2) = 64*t the easiest way to go on is to divide by 96
(t - 2) = 64t/96
t - 2 = 0.667t Subtract 0.667t from both sides.
t - 0.667t - 2 = 0 Add 2 to both sides. combine the two times
0.333t = 2 Divide by 0.333
t = 2/0.333 = 6 hours
Answer
Now solve for the distance.
d_ passenger = r_passenger * t_passenger
d_passenger = ???
r_ passenger = 96
t = 6 - 2 = 4 hours.
d = 96 * 4
d = 384 km.