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Annette [7]
3 years ago
13

An ant starts at one edge of a long strip of paper that is 34.2 cm wide. She travels at 0.4 cm/s at an angle of 52◦ with the lon

g edge. How long will it take her to get across? Answer in units of s.
Physics
1 answer:
nordsb [41]3 years ago
5 0

Answer:

t=108.50s

Explanation:

The ant is under an uniform motion. So, we get the time taken by the ant to cross the strip from the definition of speed:

v=\frac{x}{t}\\t=\frac{x}{v}

In this case, we use the vertical speed of the ant (v_y=vsin\theta), since the ant crosses the strip that is 34.2 cm wide (vertically). So:

t=\frac{y}{v_y}\\t=\frac{y}{vsin\theta}\\t=\frac{34.2cm}{0.4\frac{cm}{s}sin(52^\circ)}\\t=108.50s

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Analysis: (use a separate sheet of paper)
Zolol [24]

Speed, frequency and wavelength are interconnected to each other.

<h3>What happens to the wavelength if the frequency increases?</h3>

As a wavelength increases in size, its frequency and energy (E) decrease. As the frequency increases, the wavelength gets shorter. As the frequency decreases, the wavelength gets longer.

The wave speed is equal to the product of its frequency and wavelength, which shows the relationship between frequency and wavelength.

So we can conclude that speed, frequency and wavelength are interconnected to each other.

Learn more about frequency here: brainly.com/question/254161

5 0
2 years ago
A ball is pushed into a spring-loaded launcher with a force of 20 N, which compresses the spring 0.08 m.
damaskus [11]

Answer:

0.8J

Explanation:

Given parameters:

Force  = 20N

Compression  = 0.08m

Unknown:

Spring constant  = ?

Elastic potential energy  = ?

Solution:

To solve this problem, we use the expression below:

           F = k e

F is the force

k is the spring constant

e is the compression

             20  = k x 0.08

              k  = 250N/m

Elastic potential energy;

       EPE  = \frac{1}{2} k e²    =  \frac{1}{2}  x 250 x 0.08²

 Elastic potential energy = 0.8J

3 0
2 years ago
What is the acceleration experienced by a car that takes 10s to reach 27m/s from rest
Lerok [7]

|acceleration|  =  (change in speed) / (time for the change)

Change in the car's speed = (27 - 0) = 27 m/s
Time for the change  =  10 sec

|acceleration| = (27 m/s) / (10 s)  =  2.7 m/s² .

That's the magnitude of the car's acceleration.
We don't know anything about its direction.
5 0
3 years ago
PLEASE HELP
Sergeu [11.5K]

The vertical component of the initial velocity is v_0_y = \frac{y}{t} + \frac{1}{2} gt

The horizontal component of the initial velocity is v_0_x = \frac{x}{t}

The horizontal displacement when the object reaches maximum height is X = \frac{xy}{gt^2} + \frac{x}{2}

The given parameters;

the horizontal displacement of the object, = x

the vertical displacement of the object, = y

acceleration due to gravity, = g

time of motion, = t

The vertical component of the initial velocity is given as;

y = v_0_yt - \frac{1}{2} gt^2\\\\v_0_yt = y + \frac{1}{2} gt^2\\\\v_0_y = \frac{y}{t} + \frac{1}{2} gt

The horizontal component of the initial velocity is calculated as;

x = v_0_xt\\\\v_0_x = \frac{x}{t}

The time to reach to the maximum height is calculated as;

T = \frac{v_f_y -v_0_y}{-g} \\\\T = \frac{-v_0_y}{-g} \\\\T = \frac{v_0_y}{g} \\\\T =  \frac{1}{g}  (v_0_y)\\\\T = \frac{1}{g} (\frac{y}{t} + \frac{1}{2} gt)\\\\T = \frac{y}{gt} + \frac{1}{2} t

The horizontal displacement when the object reaches maximum height is calculated as;

X= v_0_x \times T\\\\X= \frac{x}{t} \times (\frac{y}{gt} + \frac{1}{2} t)\\\\X = \frac{xy}{gt^2} + \frac{x}{2}

Learn more here: brainly.com/question/20689870

8 0
3 years ago
If the wavelength of a wave increases does its frequency also increase?
irinina [24]
Frequency decreases whilst wavelength increases and the opposite also occurs
4 0
3 years ago
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