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Annette [7]
3 years ago
13

An ant starts at one edge of a long strip of paper that is 34.2 cm wide. She travels at 0.4 cm/s at an angle of 52◦ with the lon

g edge. How long will it take her to get across? Answer in units of s.
Physics
1 answer:
nordsb [41]3 years ago
5 0

Answer:

t=108.50s

Explanation:

The ant is under an uniform motion. So, we get the time taken by the ant to cross the strip from the definition of speed:

v=\frac{x}{t}\\t=\frac{x}{v}

In this case, we use the vertical speed of the ant (v_y=vsin\theta), since the ant crosses the strip that is 34.2 cm wide (vertically). So:

t=\frac{y}{v_y}\\t=\frac{y}{vsin\theta}\\t=\frac{34.2cm}{0.4\frac{cm}{s}sin(52^\circ)}\\t=108.50s

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Explanation:

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What determines if a material is a conductor or an insulator? Explain your answer and provide at least one example of each.
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3 years ago
The moon orbits the earth at a distance of 3.85 x 10^8 m. Assume that this distance is between the centers of the earth and the
Inga [223]

Answer:

27.5 days

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Explanation:

r = radius of the orbit of moon around the earth = 3.85\times10^{8} m

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T = Time period of moon's motion

According to Kepler's third law, Time period is related to radius of orbit as

T^{2} = \frac{4\pi ^{2} r^{3}  }{GM}

inserting the values, we get

T^{2} = \frac{4(3.14)^{2} (3.85\times10^{8})^{3}  }{(6.67\times10^{-11})(5.98\times10^{24})}\\T = 2.3754\times10^{6} sec

we know that

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6 0
3 years ago
If you pull horizontally on a desk with a force of 150 N and the desk doesn't move, the friction force must be 150 N. Now if you
s344n2d4d5 [400]

Answer:

The friction force is 250 N

Explanation:

The desk is moving at constant velocity. This means that its acceleration is zero: a = 0. Newton's second law states that the resultant of the forces acting on the desk is equal to the product between mass (m) and acceleration (a):

\sum F=ma

In this case, we know that the acceleration is zero: a = 0, so also the resultant of the forces must be zero:

\sum F = 0 (1)

We are only interested in the forces acting along the horizontal direction, since it is the direction of motion. There are two forces acting in this direction:

- the pull, forward, F = 250 N

- the friction force, backward, F_f

Given (1), we have

F-F_f = 0

So the force of friction must be equal to the pull:

F=F_f = 250 N

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Answer:

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