Question

At what distance is the electrostatic force between two protons equal to the weight of one proton?

Answer 1

Answer:

The distance between two protons is 37 cm.                    

Explanation:

The electric force between two electric charges is given by :

$F=k\dfrac{q_1q_2}{d^2}$

Here,

k is the electrostatic force

d is the separation between charges

$q_1\ and\ q_2$ are charges

According to given condition, the electrostatic force between two protons equal to the weight of one proton. So,

$W_p=\dfrac{kq^2}{d^2}$

$d=\sqrt{\dfrac{kq^2}{W_p}}$

As protons are very small particle, W = m

$d=\sqrt{\dfrac{kq^2}{m}}$

$d=\sqrt{\dfrac{9\times 10^9\times (1.6\times 10^{-19})^2}{(1.67\times 10^{-27})}}$

d = 0.37 m

or

d = 37 cm

So, the distance between two protons is 37 cm. Hence, this is the required solution.