How long will it take an object traveling at 7 m/s to reach a distance of 26 meters
1 answer:
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Answer:
The rope must have a force of 10084,21 N
Explanation
Acceleration calculation
The car acceleration is equal to the acceleration of the truck
ac: car acceleration
at: truck acceleration)
equation(1)
Known information:
vi = Initial speed = 0, ti = initial time = 0
vf = Final speed = 13 , t = final time =5 s
We replaced the known information in the equation(1):
Dynamic analysis
The forces acting on the car are the following:
Wc: Car weight
N: normal force, road force on the car
Ff: Friction force
T: Force of tension
Car weight calculation:
mc = Car mass = 2230kg
g = Gravity acceleration=9.8
Normal force calculation:
Newton's first law
Friction force calculation (Ff):
We have the formula to calculate the friction force:
Ff = μk * N Equation (3)
μk kinetic coefficient of friction
We know that μk = 0.373and N= 21854N ,then:
Calculation of the tension force in the rope (T):
Newton's Second law
T=10084,21 N
Answer: The rope must have a force of 10084,21 N
≈40.8kg
this is to take up space
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
m
=
W
g
=
400
N
9.8
m/s
2
≈
40.8
kg
