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11111nata11111 [884]
3 years ago
6

Stirring a liquid while you are mixing in another ingredient speeds up the rate of dissolving. Question 13 options: True False

Chemistry
2 answers:
brilliants [131]3 years ago
8 0

Answer:

true

Explanation:

This is because it helps distribute the particles that are being dissolved. 

Aliun [14]3 years ago
3 0
The answer would be true
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What are the substances making up a mixture called
dimulka [17.4K]

  • The substance that made up of a particular mixture can be regarded as Solute and solvent

  • A  mixture can be regarded as material which is made up of  more than one  different Chemical substance or substances , whereby they  are not chemically combined.

  • Substance could be any matter such as <em>salt, rice, and or compounds</em>

  • A mixture can be regarded as physical combination involving two or more substances whereby each entities identities are retained, then mixed in the form such as ;
  1. <em>solutions</em>
  2. <em> suspensions </em>
  3. <em> colloids</em>.

  • A mixture could be  in this form <em>(Solute + solvent = solution)</em>

Therefore, the substance that made up of a particular mixture can be regarded as <em>Solute and solvent</em>

Learn more at: brainly.com/question/18569341

7 0
3 years ago
Which of the following is a chemical change?
ValentinkaMS [17]
Answer: A - it is changing into a new substance

the other answers are just physical changes
4 0
3 years ago
A sample of methane collected when the temp was 30 C mmHg measures 398 mL. What would be the volume of the sample at -5 C and 61
Levart [38]
<h2>Question </h2>

A sample of methane collected when the temp was 30 C and 760mmHg measures 398 mL. What would be the volume of the sample at -5 C and 616 mmHg pressure

<h2>Answer:</h2>

434.32mL

<h2>Explanation:</h2>

Using the combined gas law:

\frac{PV}{T} = k

Where;

P = Pressure

V = Volume

T = Temperature

k = constant.

It can be deduced that:

\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2} = k           ---------------------(i)

Where:

P₁ and P₂ are the initial and final pressures of the given gas

V₁ and V₂ are the initial and final volumes of the given gas

T₁ and T₂ are the initial and final temperatures of the gas.

<em>From the question:</em>

the gas is methane

P₁  = 760mmHg

P₂ = 616mmHg

V₁ = 398mL

V₂ = ?

T₁ = 30°C = (30 +273)K = 303K

T₂ = -5°C = (-5 +273)K = 268K

Substitute these values into equation (i) as follows;

\frac{760*398}{303} = \frac{616*V_2}{268}

Solve for V₂

V₂ = \frac{760*398*268}{616*303}

V₂ = 434.32mL

Therefore, the volume of the sample at -5C and 616mmHg pressure is 434.32mL

5 0
3 years ago
Miss White wants to make a (decidedly not poisoned) apple pie. The recipe she is
Rina8888 [55]
So you have to multiply 786,3 times 0.98 to get the mass the mass is 770.57 if u round its 770.6 or 771
5 0
3 years ago
6 How many moles are in a 321 g sample of magnesium?
Tatiana [17]

Answer:

13.4mol of Mg

Explanation:

Given parameters:

Mass of magnesium = 321g

Unknown:

Number of moles  = ?

Solution:

The number of moles of a substance is given as;

  Number of moles  = \frac{mass}{molar mass}  

 Molar mass of Mg = 24g/mol

 Insert the parameters and solve;

        Number of moles  = \frac{321}{24}   = 13.4mol of Mg

3 0
3 years ago
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