Answer:
The structure for the compound elucidated (4-Ethylbenzoic acid) is attached below.
Explanation:
Degree of Unsaturation = (where n = no of moles)
=
= 9 - 6+1 = 4
⇒ 2 ring. 3 double bonds.
From the 1H NMR data given (peaks labeled A-E)
A. 1.2 (3H, t) ⇒ -CH3
B. 2.6 (2H, q) ⇒ -C=C-H or Aromatic-CH3
C. 7.3 (2H, d) ⇒ Aro.-H
D. 8.0 (2H, d) ⇒ Aro.-H
E. 11.0 (1H, s) ⇒ -COOH
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The correct answer is Carbon Dioxide.
<h3>
What are carbon bonds?</h3>
- Because each carbon is identical, they all contain four valence electrons, so they can easily bond with different carbon atoms to form extended chains or rings. A carbon atom can bond with another carbon atom two or three times to create double and triple covalent adhesives between two carbon atoms.
- The partial payments on the fluorine and carbon are beautiful, contributing to the unusual bond power of the carbon-fluorine bond. The bond is marked as "the strongest in organic chemistry," because fluorine forms the strongest single bond to carbon.
- In chemistry, a covalent bond is the strongest bond. In such bonding, every two atoms transfer electrons that bind them concurrently. For example, water molecules are bonded jointly where both hydrogen atoms and oxygen atoms transfer electrons to form a covalent bond.
To learn more about carbon bonds, refer to:
brainly.com/question/14700099
#SPJ4
Answer:
0.1738 M
Explanation:
Let's consider the neutralization reaction between NaOH and HBr.
NaOH + HBr → NaBr + H₂O
The moles of HBr are:
14.76 × 10⁻³ L × 0.4122 mol/L = 6.084 × 10⁻³ mol
The molar ratio of NaOH to HBr is 1:1. In the endpoint, they have reacted completely, so the moles of NaOH were 6.084 × 10⁻³ mol before the reaction.
The molarity of NaOH is:
M = 6.084 × 10⁻³ mol / 35.00 × 10⁻³ L = 0.1738 M