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Vera_Pavlovna [14]
3 years ago
8

Compounds A and B are constitutional isomers (same molecular formula but

Chemistry
1 answer:
Naily [24]3 years ago
3 0

Answer:

Trimethylacetaldehyde

Explanation:

For the <u>unknow compound</u> we have a molar mass of 86 g/mol. We have an even value for the mass, so the compound does <u>not have nitrogen</u> and we can have several posibilities:

A) C_3H_2O_3

B) C_4H_6O_2

C) C_5H_1_0O

D) C_6H_1_4

If we check the IR info a signal in 1730 cm-1 appears, this indicates that we have an <u>oxo group</u> (C=O). So, the D option can be discarded. The groups that can have the oxo group are: Carboxylic acids, <u>Ketones and aldehydes</u>.

We don have a signal in 3000 cm-1, so the carboxylic acid can be discarded. Now, is we check the info for the 1H NMR we only have 2 signals. If we only have 2 we will have a very<u> symmetric compound</u>.

By trial an error the find the compound <u>Trimethylacetaldehyde</u> (Figure 1).

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