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olga55 [171]
3 years ago
5

If 15.00 mL of 0.0100 M Ca(IO3)2 solution are mixed with 0.500 g KI, what is the theoretical yield (in grams) of I2?

Chemistry
1 answer:
n200080 [17]3 years ago
8 0

The theoretical yield of I2 in the reaction would be 0.23 g

<h3>Theoretical yield</h3>

This refers to the stoichiometric yield of a reaction.

From the equation of the reaction:

Ca(IO3)2 + 10 KI + 12 HCl → 6 I2 + CaCl2 + 10 KCl + 6 H2O

The mole ratio of Ca(IO3)2 and I2 is 1: 6

Mole of 15.00 mL, 0.0100 M Ca(IO3)2 = 15/1000 x 0.0100

                                                              = 0.00015 mole

Equivalent mole of I2 = 0.00015 x 6

                                      = 0.009 mole

mass of 0.0009 I2 = 0.0009 x 253.809

                                = 0.23 g

More on stoichiometric calculations can be found here: brainly.com/question/6907332

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yulyashka [42]

15.63 moles of HgO are needed to produce 250. 0 grams of Oxygen.

<h3>How we calculate moles from masses?</h3>

Moles of any substance can be calculated as:

n =W/M, where

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M = molar mass

Given chemical reaction is:

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From the stoichiometry of the reaction, it is clear that:

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Molar mass of O₂ = 32 g/mole

Mole of produced O₂ = 250g / 32g/mole = 7.81 moles

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Hence, option (3) is correct i.e. 15.63 moles is the required moles.

To know more about moles, visit the below link:

brainly.com/question/16060223

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