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-Dominant- [34]
3 years ago
6

(2) Describe how a chemical bond forms between a Group 1 element and a Group 17 element.

Chemistry
2 answers:
creativ13 [48]3 years ago
5 0

Since elements in group 1 only have 1 valence electron and elements in group 17 have 7 valence electrons, the one electron from the element in group 1 transfers to the group 17 element. That way, there are 8 valence electrons in this new bond, or a full outer energy level!

Dmitry_Shevchenko [17]3 years ago
4 0
Ionicly

They do not share electrons. All of the electrons get attracted the the group 7 element and they stick together electrostaticly.
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The energy of a pendulum is recorded at different positions in the table below. Use the data in the table to determine the amoun
natta225 [31]

Answer:

36.55 J

Explanation:

PE = Potential energy

KE = Kinetic energy

TE = Total energy

The following data were obtained from the question:

Position >> PE >>>>> KE >>>>>> TE

1 >>>>>>>> 72.26 >> 27.74 >>>> 100

2 >>>>>>>> 63.45 >> x >>>>>>>> 100

3 >>>>>>>> 58.09 >> 41.91 >>>>> 100

The kinetic energy of the pendulum at position 2 can be obtained as follow:

From the table above, at position 2,

Potential energy (PE) = 63.45 J

Kinetic energy (KE) = unknown = x

Total energy (TE) = 100 J

TE = PE + KE

100 = 63.45 + x

Collect like terms

100 – 63.45 = x

x = 36.55 J

Thus, the kinetic energy of the pendulum at position 2 is 36.55 J.

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2 years ago
2+2=? -1 3 quick math
tino4ka555 [31]
EVERYDAY MANS ON THE BLOCK. Lol its 4. You got this from Mans Not Hot, didn't you? xD
4 0
3 years ago
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Draw the alkene formed when 1-heptyne is treated with hbr in the presence of peroxide.
Nimfa-mama [501]
<h2>Heptene formed is -</h2><h2>CH_3-CH_2-CH_2-CH_2-CH_2-CH=CHBr</h2>

Explanation:

The two possibilities when the peroxide is not present

  • CH_{3}-CH_{2}-CH_{2}-CH_{2}-CH_{2}-C≡CH +HBr → CH_3-CH_2-CH_2-CH_2-CH_2-CBr=CH_{2}

  • CH_3-CH_2-CH_2-CH_2-CH_2-CBr=CH_2 + HBr →CH_3-CH_2-CH_2-CH_2-CH_2-CBr_2-CH_3

In presence peroxide,

CH_3-CH_2-CH_2-CH_2-CH_2-C≡CH+ HBr →CH_3-CH_2-CH_2-CH_2-CH_2-CH=CHBr

  • When peroxides are present in the reaction mixture, hydrogen bromide adds to the triple bond of heptane with regioselectivity.
  • This reaction is opposite to that of Markovnikov's rule which says that when asymmetrical alkene reacts with a protic acid HX, then the hydrogen of an acid is attached to the carbon with more in number of hydrogen substituents, and the halide (X) group is attached to the carbon with more in number of substituents of alkyl.
  • One mole of HBr adds to one mole of 1-heptane.
  • The structure of heptene formed is -

CH_3-CH_2-CH_2-CH_2-CH_2-CH=CHBr

5 0
3 years ago
The number of molecules in 7g nitrogen​
charle [14.2K]

Answer:

the number of molecules in 7g nitrogen

Ans) 7 gram of Nitrogen contains 1.5×10^23 molecules =1.5e+23

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3 years ago
Which of the following chemical equations is correctly balanced?
olga55 [171]
The correct answer is B.
3 0
3 years ago
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