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-Dominant- [34]
2 years ago
6

(2) Describe how a chemical bond forms between a Group 1 element and a Group 17 element.

Chemistry
2 answers:
creativ13 [48]2 years ago
5 0

Since elements in group 1 only have 1 valence electron and elements in group 17 have 7 valence electrons, the one electron from the element in group 1 transfers to the group 17 element. That way, there are 8 valence electrons in this new bond, or a full outer energy level!

Dmitry_Shevchenko [17]2 years ago
4 0
Ionicly

They do not share electrons. All of the electrons get attracted the the group 7 element and they stick together electrostaticly.
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The photodissociation of ozone by ultraviolet light in the upper atmosphere is a first-order reaction with a rate constant of 1.
atroni [7]

Answer:

[O₃]= 8.84x10⁻⁷M  

Explanation:

<u>The photodissociation of ozone by UV light is given by:</u>

O₃ + hν → O₂ + O (1)

<u>The first-order reaction of the equation (1) is:</u>

rate = k [O_{3}] = - k \frac{\Delta [O_{3}]}{\Delta t} (2)

<em>where k: is the rate constant and Δ[O₃]/Δt: is the variation in the ozone concentration with time, and the negative sign is by the decrease in the reactant concentration </em>    

<u>We can get the following expression of the </u><u>first-order integrated law</u><u> of the reaction (1), by resolving the equation (2):</u>

[O_{3}]_{t} = [O_{3}]_{0} \cdot e^{-kt} (3)

<em>where [O₃](t): is the ozone concentration in the elapsed time and [O₃]₀: is the initial ozone concentration</em>

We can calculate the initial ozone concentration using equation (3):  

[O_{3}]_{t} = 5.0 \cdot 10^{-3}M \cdot e^{-(1.0\cdot 10^{-5}s^{-1}) (\frac{10d \cdot 24h \cdot 3600 s}{1d \cdot 1h})} = 8.84 \cdot 10^{-7}M

So, the ozone concentration after 10 days is 8.84x10⁻⁷M.

I hope it helps you!                    

3 0
3 years ago
Circle the letter of cach sentence that is true about silica.
miskamm [114]
The answer is either A or B I’m not sure
7 0
3 years ago
Read 2 more answers
Round off the following measurement to three significant figures. 1.296 g
REY [17]
It would be 1 or 2 because if the number is higher than 5 you need to round up , if its lower than 5 you need to round down.

7 0
3 years ago
A nitrogen atom in N2 should have a
SIZIF [17.4K]

Answer:

The answer is partial charge 8+.

7 0
2 years ago
When one mole of a solute is present in 500 cm3 of solution, then the concentration of the solution is:
Schach [20]

Answer:

0.5M is the answer.

Explanation:

1M solution is the solution containing 1mole solute dissolved per litre of solution.

Using unitary method,

1000cc gives 1M.

1cc gives 1/1000M.

500 cc gives 500/1000M=0.5M

7 0
3 years ago
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