Answer:
11.65 g
Explanation:
Amount of NaCl = 15.0 grams
amount of H₂SO₄ = Excess
mass of hydrochloric acid (HCl) = ?
Solution:
To solve this problem first we will look for the reaction that NaCl react with H₂SO₄
Reaction:
2NaCl + H₂SO₄ --------> 2 HCl + Na₂SO₄
As the H₂SO₄ is in excess so the amount of hydrochloric acid (HCl) depends on the amount of NaCl as it its act as limiting reactant.
Now if we look at the reaction
2NaCl + H₂SO₄ --------> 2HCl + Na₂SO₄
1 mol 2 mol
Now convert moles to mass
Then
Molar mass of NaCl = 23 + 35.5 = 58.5 g/mol
Molar mass of HCl = 1 + 35.5 = 36.5 g/mol
So,
2NaCl + H₂SO₄ --------> 2HCl + Na₂SO₄
2 mol (58.5 g/mol) 2 mol (36.5 g/mol)
94 g 73 g
So if we look at the reaction; 94 g of NaCl gives with 73 g of hydrochloric acid (HCl) in a this reaction, then how many grams of hydrochloric acid (HCl) will produce from 15.0 g of NaCl
For this apply unity formula
94 g of NaCl ≅ 73 g of HCl
15.0 g of NaCl ≅ X g of HCl
By Doing cross multiplication
X g of HCl = 73 g x 15.0 g / 94 g
X g of HCl = 11.65 g
11.65 g of hydrochloric acid (HCl) will produce by 15.0 g of NaCl
