A chemistry student needs of 65 gr acetyl bromide for an experiment. She has available 20 g of 38.1 % a w/w solution of acetyl b
1 answer:
This is an incomplete question, here is a complete question.
A chemistry student needs 65.0g acetyl bromide for an experiment. He has available 20.0 g of a 38.1 % w/w solution of acetyl bromide in diethyl ether. Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button.
Answer : The correct answer is "No solution".
Explanation :
As we are given that 38.1 % w/w solution of heptane in chloroform. That means 38.1 gram of heptane present in 100 gram of solution.
Now we have to determine the mass of solution for 65.0 grams of hepatne.
As, 38.1 grams of heptane present in 100 grams of solution
So, 65.0 grams of heptane present in grams of solution
Since, there is only 20.0 grams of solution available. That means, there is not enough solution.
Thus, the correct answer is "No solution".
You might be interested in
Answer: Option (5) is the correct answer.
Explanation:
It is known that the ground state electronic configuration of silicon is .
And, we know that when an atom tends to gain an electron then it acquires a negative charge and when an atom tends to lose an electron then it acquires a positive charge.
As has a +4 charge which means that it has lost 4 electrons. Hence, the electronic configuration of
is
.
According to the Aufbau principle, in the ground state of an atom or ion the electrons fill atomic orbitals of the lowest energy levels first, before filling the higher energy levels.
As 2p orbital is filled after the filling of 2s orbital.
Therefore, we can conclude that 2p orbital will be occupied by the electrons of highest energy for the ground-state ion.
Answer : The volume of oxygen at STP is 112.0665 L
Solution : Given,
The number of moles of = 5 moles
At STP, the temperature is 273 K and pressure is 1 atm.
Using ideal gas law equation :
where,
P = pressure of gas
V = volume of gas
n = the number of moles
T = temperature of gas
R = gas constant = 0.0821 L atm/mole K (Given)
By rearranging the above ideal gas law equation, we get
Now put all the given values in this expression, we get the value of volume.
Therefore, the volume of oxygen at STP is 112.0665 L