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snow_tiger [21]
3 years ago
7

A chemistry student needs of 65 gr acetyl bromide for an experiment. She has available 20 g of 38.1 % a w/w solution of acetyl b

romide in diethyl ether. Calculate the mass of solution the student should use.
Chemistry
1 answer:
zzz [600]3 years ago
5 0

This is an incomplete question, here is a complete question.

A chemistry student needs 65.0g acetyl bromide for an experiment. He has available 20.0 g of a 38.1 % w/w solution of acetyl bromide in diethyl ether. Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button.

Answer : The correct answer is "No solution".

Explanation :

As we are given that 38.1 % w/w solution of heptane in chloroform. That means 38.1 gram of heptane present in 100 gram of solution.

Now we have to determine the mass of solution for 65.0 grams of hepatne.

As, 38.1 grams of heptane present in 100 grams of solution

So, 65.0 grams of heptane present in \frac{65.0}{38.1}\times 100=171 grams of solution

Since, there is only 20.0 grams of solution available. That means, there is not enough solution.

Thus, the correct answer is "No solution".

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9. During an experiment the students prepared three mixtures A)Starch in water B) Sodium chloride solution C) Tincture of Iodine
il63 [147K]

Answer:

See explanation

Explanation:

Tyndall effect refers to the scattering of light in a solution. Tyndall effect occurs when the size of particles in the solution exceeds 1 nm in diameter. Such solutions are actually called false solutions.

In tincture of iodine, the size of particles in solution is less than 1 nm in diameter hence the solution does not exhibit Tyndall effect. Hence, tincture of iodine is a true solution.

Therefore, if the size of particles in solution exceeded 1nm in diameter, Tyndall effect is observed.

7 0
3 years ago
If D+2 would react with E!, what do you predict to be the formula?
kherson [118]

Answer:

I think the answers D. Hope this helps you.

Explanation:

6 0
3 years ago
Consider a galvanic cell consisting of the following two redox couplesAlB+ 3e Al , Mga + 2e Mg, (ag. E® = 1.676 V ) E° = 2.356 V
malfutka [58]

Answer:

0.68 V

Explanation:

For anode;

3Mg(s) ---->3Mg^2+(aq) + 6e

For cathode;

2Al^3+(aq) + 6e -----> 2Al(s)

Overall balanced reaction equation;

3Mg(s) + 2Al^3+(aq) ----> 3Mg^2+(aq) + 2Al(s)

Since

E°anode = -2.356 V

E°cathode = -1.676 V

E°cell=-1.676 -(-2.356)

E°cell= 0.68 V

4 0
3 years ago
What are the two categories of chemical sedimentary rock?
AnnyKZ [126]
Calcite and calcite?
4 0
3 years ago
HELPP! pls
pshichka [43]

Answer:

"2.48 mole" of H₂ are formed. A further explanation is provided below.

Explanation:

The given values are:

Mole of Al,

= 3.22 mole

Mole of HBr,

= 4.96 mole

Now,

(a)

The number of mole of H₂ are:

⇒  \frac{Mole \ of \ H_2}{3} =\frac{Mole \ of HBr}{6}

or,

⇒  Mole \ of \ H_2=\frac{1}{2}\times Mole \ of \ HBr

⇒                      =\frac{1}{2}\times 4.96

⇒                      =2.48 \ mole

(b)

The limiting reactant is:

= HBr

(c)

The excess reactant is:

= Al

6 0
2 years ago
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