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snow_tiger [21]
3 years ago
7

A chemistry student needs of 65 gr acetyl bromide for an experiment. She has available 20 g of 38.1 % a w/w solution of acetyl b

romide in diethyl ether. Calculate the mass of solution the student should use.
Chemistry
1 answer:
zzz [600]3 years ago
5 0

This is an incomplete question, here is a complete question.

A chemistry student needs 65.0g acetyl bromide for an experiment. He has available 20.0 g of a 38.1 % w/w solution of acetyl bromide in diethyl ether. Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button.

Answer : The correct answer is "No solution".

Explanation :

As we are given that 38.1 % w/w solution of heptane in chloroform. That means 38.1 gram of heptane present in 100 gram of solution.

Now we have to determine the mass of solution for 65.0 grams of hepatne.

As, 38.1 grams of heptane present in 100 grams of solution

So, 65.0 grams of heptane present in \frac{65.0}{38.1}\times 100=171 grams of solution

Since, there is only 20.0 grams of solution available. That means, there is not enough solution.

Thus, the correct answer is "No solution".

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The amount of water that will be produced is 50.36 grams

<h3>Stoichiometric problems</h3>

The metabolism of glucose is represented by the following equation:

C_6H_1_2O_6(s)+6O_2(g)--- > 6CO_2(g)+6H_2O(g)

The mole ratio of glucose metabolized to the water produced is 1:6.

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More on stoichiometric problems can be found here: brainly.com/question/14465605

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74,67 gr/mol

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