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likoan [24]
2 years ago
15

Cocaine (C₁₇H₂₁O₄N) is a natural substance found in coca leaves, which have been used for centuries as a local anesthetic and st

imulant. Illegal cocaine arrives in the United States either as the pure compound or as the hydrochloride salt (C₁₇H₂₁O₄NHCL). At 25°C, the salt is very soluble in water (2.50 kg/L), but cocaine is much less so (1.70 g/L).
(a) What is the maximum mass (g) of the salt that can dissolve in 50.0 mL of water?
Chemistry
1 answer:
Fynjy0 [20]2 years ago
4 0

The saturation level is only nominally dependent on the temperature of the water. At 20 °C one liter of water can dissolve about 357 grams of salt, a concentration of 26.3% w/w. At boiling (100 °C) the amount that can be dissolved in one liter of water increases to about 391 grams, a concentration of 28.1% w/w.

<h3>How do you calculate the solubility of salt in water?</h3>

Divide the mass of the compound by the mass of the solvent and then multiply by 100 g to calculate the solubility in g/100g .

<h3>How do you calculate the concentration of salt in water?</h3>

Salt is the solute (the dissolving substance), and water is the solvent (the substance that dissolves another to create a solution). To make a salt solution by weight percent (w/v), you apply the formula w/v = (mass of solute ÷ volume of solution) × 100.

Learn more about solubility here:

<h3>brainly.com/question/23946616</h3><h3 /><h3>#SPJ4</h3>
You might be interested in
What is the molarity of a HCl solution, if 28.6 mL of a 0.175 m NaOH solution is needed to neutralize a 25.0 mL sample of the HC
Katen [24]

The molarity of the HCl solution needed to neutralize 28.6 mL of a 0.175 M NaOH solution is 0.2002 M

We'll begin by writing the balanced equation for the reaction. This is given below:

HCl + NaOH —> NaCl + H₂O

From the balanced equation above,

The mole ratio of the acid, HCl (nA) = 1

The mole ratio of the base, NaOH (nB) = 1

  • From the question given above, the following data were obtained:

Volume of base, NaOH (Vb) = 28.6 mL

Molarity of base, NaOH (Mb) = 0.175 M

Volume of acid, HCl (Va) = 25 mL

<h3>Molarity of acid, HCl (Ma) = ?</h3>

The molarity of the acid, HCl can be obtained as follow:

MaVa / MbVb = nA / nB

(Ma × 25) / (0.175 × 28.6) = 1

(Ma × 25) / 5.005 = 1

Cross multiply

Ma × 25 = 5.005

Divide both side by 25

Ma = 5.005 / 25

<h3>Ma = 0.2002 M</h3>

Therefore, the molarity of the acid, HCl needed for the reaction is 0.2002 M

Learn more: brainly.com/question/25573711

7 0
3 years ago
How can I tell how many neutrons there are in an element
icang [17]
It all depends on if you know the mass number and atomic number then you will be able to find out what the amount of neutron in an element.
7 0
3 years ago
Which side of the electromagnetic spectrum has shorter wavelengths
kondaur [170]

Answer:blue blue blue

Explanation:

Just answered it and got it right

7 0
3 years ago
Read 2 more answers
Which of the following an inorganic compound?
oksano4ka [1.4K]
An organic compound is one which consists of a chain of carbon atoms with other atoms bonded to the chain.

Pentane has 5 carbon atoms with surrounding hydrogens.
glucose is a chain of 6 carbon atoms
butane is similar to pentane

water has no carbon atoms, and the central atom is oxygen ---> therefore it is inorganic!
8 0
4 years ago
For the reaction 2Na + Cl2 → 2NaCl, how many grams of chlorine gas are required to react completely with 57.5 mol of sodium?
Step2247 [10]

Answer:

1019.27 g.

Explanation:

  • For the balanced reaction:

<em>2Na + Cl₂ → 2NaCl,</em>

It is clear 2 moles of Na with 1 mole of Cl₂ to produce 2 moles NaCl.

  • Firstly, we need to calculate the no. of moles of Cl₂ is needed to react with 57.5 mol Na:

2 moles of Na need → 1 mol of Cl₂, from the stichiometry.

57.5 moles of Na need → ??? mol of Cl₂.

<em>∴ The no. of moles of Cl₂ is needed to react with 57.5 mol Na =</em> (1 mol)(57.5 mol)/((2 mol) <em>= 28.75 mol.</em>

<em>∴ the mass of Cl₂ is needed to react with 57.5 mol Na = (no. of moles of Cl₂)(molar mass of Cl₂) =</em> (28.75 mol)(35.453 g/mol) <em>= 1019.27 g.</em>

4 0
3 years ago
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