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Liono4ka [1.6K]

3 years ago

5

When the cations Na+, K+, Rb+, Cs+ are combined with chloride ion in the gas phase to form ion pairs, which pair formation relea

ses the greatest amount of energy?

2 answers:

Luden [163]3 years ago

7 0

Answer:

Rb+ and chlorine.

Explanation:

Rb+ and chlorine - Rubidium is the furthest down Group of the Periodic Table and reacts more vigorously than the others.

Gemiola [76]3 years ago

5 0

Answer:

NaCl

Explanation:

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A chemist is using radiation with a frequency of 6.0 x 10^13 Hz

kirza4 [7]

Answer:

λ = 0.5×10⁻⁵ m

E = 39.78×10⁻²¹ J

The given radiation is gamma ray.

Explanation:

Given data:

Frequency of radiation = 6.0 ×10¹³ Hz

Wavelength of radiation = ?

Type of radiation = ?

Energy of radiation = ?

Solution:

Formula:

speed of light = wavelength × frequency

3 ×10⁸ m/s = λ × 6.0 ×10¹³ Hz

Hz = s⁻¹

λ = 3 ×10⁸ m/s / 6.0 ×10¹³ s⁻¹

λ = 0.5×10⁻⁵ m

Energy of radiation:

E = hf

h = planck's constant

f = frequency

E = 6.63×10⁻³⁴ j.s × 6.0 ×10¹³ s⁻¹

E = 39.78×10⁻²¹ J

The given radiation is gamma ray.

4 0

3 years ago

How to prepare 250.00 ml of approximately 1.0 m hcl solution from the 2.5 m hcl solutio?

kirill115 [55]

To solve this we use the equation,

M1V1 = M2V2

where M1 is the concentration of the stock solution, V1 is the volume of the stock solution, M2 is the concentration of the new solution and V2 is its volume.

2.5 M x V1 = 1.0 M x .250 L

<span>V1 = 0.10 L or 100 mL of the 2.5 M HCl solution is needed

Hope this helps.</span>

4 0

3 years ago

Read 2 more answers

Give two test substances that would react with each other to produce salt and water

Mademuasel [1]

Answer:

NaOH +HCl==>Nacl+H2O

KOH+HCl==>KOH+H2O

6 0

3 years ago

xenn [34]

Answer:

Its C hope it helped

Explanation:

3 0

3 years ago

Write the balanced equation. Then calculate the volume of 0.65 M HCl required to completely neutralize 400.0 ml of 0.88 M KOH.

Misha Larkins [42]

Hello!

The balanced equation for the neutralization of KOH is the following:

HCl(aq) + KOH(aq) → KCl(aq) + H₂O(l)

To calculate the volume of HCl required, we can apply the following equation:

$moles HCl = moles KOH \\ \\ cHCl*vHCl=cKOH*vKOH \\ \\ vHCl= \frac{cKOH*vKOH}{cHCl}= \frac{400 mL*0,88M}{0,65M}= 541,54mL$

So, the required volume of HCl is 541,54 mL

Have a nice day!

8 0

3 years ago