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nignag [31]
3 years ago
8

Isn’t urgent the first 3 will be marked BRAINIEST

Chemistry
2 answers:
valentinak56 [21]3 years ago
8 0
Aluminum Sulphate:

Al2(SO4)3

Magnesium Hydroxide:

Mg(OH)2
bearhunter [10]3 years ago
7 0

Answer:

Al2(SO4)3 and Mg(OH)2

Explanation:

1. Al has a charge of 3-, and SO4 of 2-

when you cross multiply the charges you get

Al2 and (SO4)3

*the reason theres a bracket around the sulfate ion is that the charge 3 is not for oxygen only, but the entire sulphate ion*

Hence, Al2(SO4)3

2. Mg has a charge of 2- and OH of 1-

again cross multiply

Mg (you dont need to add the 1) and (OH)2

again, the bracket around OH means the charge appiles to Oxygen AND hydrogen

hence, Mg(OH)2

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Give the o.N. Of each of the elements magnesium and oxygen in the reactants and in the products 2Mg + O2=2MgO
vlada-n [284]

Answer:

2Mg^0 + O_2^0\rightarrow2Mg^{2+}O^{2-}

Explanation:

Hello there!

In this case, according to the rules for the oxidation states in chemical reactions, it is possible to realize that lone elements have 0 and since magnesium is in group 2A, it forms the cation Mg⁺² as it loses electrons and oxygen is in group 6A so it forms the anion O⁻²; therefore resulting oxidation numbers are:

2Mg^0 + O_2^0\rightarrow2Mg^{2+}O^{2-}

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What mass of CH3COOH is present in a 250 mL cup of 1.25 mol/L solution of vinegar?
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If    1000 ml (1 L) of CH₃COOH contain 1.25 mol
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⇒  x =  \frac{250 ml * 1.25mol}{1000 ml}
        
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