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vichka [17]
3 years ago
6

Sally's index finger is 85 mm long, how long is her index finger in decimeters?

Chemistry
2 answers:
yanalaym [24]3 years ago
8 0

Answer:0.85 decimeters

Explanation:

Lubov Fominskaja [6]3 years ago
7 0

Answer: After their non invasive blood pressure, heart rate, fasting time and body ... We assume that right middle finger and right thumb have the most ...is intended to provide teachers with ideas and materials to help them in their im- ... How long will it take me to travel across town? How many boxes of candy will have to be sold ... LET YOUR FINGERS DO THE ... In the Middle Ages it was commonly used to mean computation ... The ratio'of Sally's height to Lenny's heigflt 4s.

Explanation: I hope this helps :)

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A mixture is two or more substances that are mixed together but not chemically combined. The substances in a mixture each keep t
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The answer is B because salt is NaCl.
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4 years ago
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Enter the balanced complete ionic equation for HCl(aq)+K2CO3(aq)→H2O(l)+CO2(g)+KCl(aq). Express your answer as a chemical equati
Marat540 [252]

<u>Answer:</u> The net ionic equation is given below.

<u>Explanation:</u>

Net ionic equation of any reaction does not include any spectator ions.

These ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of hydrochloric acid and potassium carbonate is given as:

2HCl(aq.)+K_2CO_3(aq.)\rightarrow H_2O(l)+CO_2(g)+2KCl(aq.)

Ionic form of the above equation follows:

2H^+(aq.)+2Cl^-(aq.)+2K^+(aq.)+CO_3^{2-}(aq.)\rightarrow CO_2(g)+H_2O(l)+2K^+(aq.)+2Cl^-(aq.)

As, potassium and chloride ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation.

The net ionic equation for the above reaction follows:

2H^+(aq.)+CO_3^{2-}(aq.)\rightarrow CO_2(g)+H_2O(l)

Hence, the net ionic equation is given above.

7 0
3 years ago
LIST TWO SUBSTANCE THAT CAN BE USED TO (i)REDUCE THE ACIDITY OF A SUBSTANCE
jenyasd209 [6]

Answer:

An acidic substance is any substance with a pH of less than 7, the smaller the number the more acidic it is. ... An acid is a substance that donates hydrogen ions. Because of this, when an acid is dissolved in water, the balance between hydrogen ions and hydroxide ions is shifted.

Explanation:

3 0
3 years ago
Which method preserves an image of a leaf?.
Sav [38]

Answer:

Tree sap flows over the leaf and preserves it.

Explanation:

Amber would preserve the image.

5 0
3 years ago
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5. What are the relative rates of diffusion for methane, CH, and oxygen, O2? If O2 la travels 1.00 m in a certain amount of time
11Alexandr11 [23.1K]

Answer:

The relative rates of diffusion for methane and oxygen is 1.4142.

Methane gas will be able to travel 1.4142 meter in the same conditions.

Explanation:

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. Mathematically written as:

\text{Rate of diffusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

We are given:

Molar mass of methane gas, m = 16 g/mol

Molar mass of oxygen gas,m' = 32 g/mol

By taking their ratio, we get:

\frac{d_{CH_4}}{d_{O_2}}=\sqrt{\frac{m'}{m}}

\frac{d_{CH_4}}{d_{O_2}}=\sqrt{\frac{32}{16}}=1.4142

The relative rates of diffusion for methane and oxygen is 1.4142.

If oxygen gas travels 1 meters in time t.

Rate of diffusion of oxygen =d_{O_2}=\frac{1 m}{t}

If methane gas travels travels in y meters in time t.

Rate of diffusion of methane=d_{CH_4}=\frac{y }{t}

\frac{d_{CH_4}}{d_{O_2}}=\frac{\frac{y }{t}}{\frac{1 m}{t}}=1.4142

y = 1.4142 m

Methane gas will be able to travel 1.4142 meter in the same conditions.

8 0
3 years ago
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