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Stolb23 [73]
2 years ago
9

S A voltage ΔV is applied to a series configuration of n resistors, each of resistance R. The circuit components are reconnected

in a parallel configuration, and voltage ΔV is again applied. Show that the power delivered to the series configuration is 1 /n² times the power delivered to the parallel configuration.
Physics
1 answer:
Flura [38]2 years ago
3 0

The power of is series combination is Vn^2 times that of a parallel combination.

For series combination :

Req = R + R + R + ............... n times = nR

I = Δv/nr

Power = (Δv/nr)^2 × nr = Δv^2/nr

For parallel combination

1/req = 1/R + 1/R + 1/R +................(n times) = n/R

Req = R/n

Power = Δv/(R/n) = nΔv^2/R

Ratio = Δv^2/nr/n·Δv^2/R = 1/n^2

Hence, power of is series combination is Vn^2 times that of a parallel.

Learn more about parallel combination here:

brainly.com/question/12400458

#SPJ4

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