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The option that correctly compares a pure substance to a mixture is: B. A pure substance can only be separated by chemical means, whereas some mixtures can be separated by physical means.

A pure substance can be defined as a substance that has a definite and constant (fixed) structure and they are typically made up of only a kind of particles. Thus, a pure substance is a chemical substance that has a constant (fixed) chemical composition and properties.

As a result of a pure substance being a chemical substance, it cannot be separated into its constituents by a physical separation technique or method.

Instead, a pure substance being a chemical substance can only be separated by chemical separation technique or method.

In contrast, mixtures can be separated by a physical separation technique or method.

Find more information: brainly.com/question/24615100

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Answer:

An apple in free fall accelerates toward the Earth with a free fall acceleration, g. The force of the apple on the Earth also causes the Earth to accelerate toward the falling apple. By Newton's Third Law, the force of the Earth on the apple is exactly equal and opposite to the force of the apple on the Earth. By Newton,s Second law, the force of the Earth on the apple is equal to the mass of the apple times g , the accelerations due to gravity. And, the force of the the apple on the Earth is equal to the mass of the Earth times the acceleration of the Earth toward the apple. In conclusion, the magnitude of the forces are equal, or

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Explanation:

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The time required by the particles are as follows:

a. t = 1.5 seconds

b. t = 3 seconds

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<h3>What is the time required?</h3>

The time required for the particles to be at several distances apart is calculated using the equation of motion given below:

$S = ut + \frac{1}{2}at^{2}$

a) Time required to be 30 m apart:

Assuming the distance covered by P is S1 and distance covered by Q is S2.

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S1 + S2 = 21

Substituting the values of velocity and acceleration in the equation of motion above:

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b) Time required to meet:

Assuming the distance covered by P is S1 and distance covered by Q is S2.

S1 + S2 = 51

Substituting the values of velocity and acceleration in the equation of motion above:

5t + 1/2t^2 + 6t + 3t^2 = 51

2t^2 + 11t - 51 = 0

Solving for time, t by factorization, t = 3 seconds

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Using the equation of motion: V = u + at

Vp = 3/4 Vq

4Vp= 3Vq

Substituting the values:

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5t = 2

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Learn more about distance, velocity and acceleration at: brainly.com/question/14344386

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