Answer:
At 11.5 m
Explanation:
The power per unit area corresponds to the intensity, which is given by

where
P is the power
is the area irradiated at a distance r from the source (it corresponds to the surface area of a sphere of radius r)
Here we want the intensity of the two light bulbs to be the same, so

where we have
P1 = 100 W is the power of the first light bulb
P2 = 75 W is the power of the second light bulb
r2 = 10 m is the distance from the second light bulb
Solving for r1, we find

Answer:
(d/λ) = 17.67
Explanation:
Equation for double-slit:
d*sinθ = m*λ
Rearrange the equation
(d/λ) = m/(sinθ)
Since it is at the second dark fringe, m = 2
Therefore:
(d/λ) = 2/(sin(6.5)
(d/λ) = 17.67
Answer:
The final kinetic energy of the Helium nucleus (alpha particle) after been scattered through an angle of 120° is
8.00 x 10-13J
Explanation:
In Rutherford Scattering experiment, the collision of the helium nucleus with the gold nucleus is an ELASTIC COLLISION. This means that the kinetic energy is conserved ( The same before and after the collision).
Thus, the final kinetic energy of the helium nucleus is the same as initial kinetic energy (8.00 x 10^-13Joules)
Although, the kinetic energy is converted to potential energy in Coulomb's law equation.
That is,
1/2(mv^2) = (K* q1q2)/r
Where m is the mass of helium nucleus, v is its colliding velocity, k is electrostatic constant, q1 is the charge on helium nucleus, q2 is the charge on gold nucleus, r is impact parameter
We have,
- Jane mass is 55 kg
- His body covered with 700 nails all of them having a surface area of 1.00 mm² each = 700 × 1 = 700 mm² = 700/1000000 = 7/10000
We know that,
Let's calculate force as we already have area;
- F = ma
- F = 55 × 9.8 { Acceleration due to gravity }
- F = 539 N
Now, if should she would be on 700 nails then pressure will be;
- P = F/A
- P = 539/7 × 10000
- P = 5390000/7
- P = 770,000 Pascal
And if should would be on a 1 nail only,
- P = F/A
- P = 539/1 × 1000000
- P = 539000000 Pascal
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Explanation:
Given that,
Two resistors of resistance 6 ohm and 3 ohm are connected in series and then in parallel.
For series combination,

For parallel combination,

When 6 ohm and 3 ohm are in series,

When 6 ohm and 3 ohm are in paralle,

So, the equivalent resistance in series combination is 9 ohms and in parallel combination it is 2 ohms.