Answer:
(a) surface area of the plate will be equal to
(b) Charge on the capacitor is equal to
Explanation:
We have given spacing between the plates d = 0.05 mm =
Value of capacitance
(A) Capacitance of a parallel plate capacitor is equal to
So
So surface area of the plate will be equal to
(B) It is given that capacitor is charged by 1.5 volt
So voltage V = 1.5 volt
Charge on the capacitor is equal to
So
Answer:
q = 3.6 10⁵ C
Explanation:
To solve this exercise, let's use one of the consequences of Gauss's law, that all the charge on a body can be considered at its center, therefore we calculate the electric field on the surface of a sphere with the radius of the Earth
r = 6 , 37 106 m
E = k q / r²
q = E r² / k
q =
q = 4.5 10⁵ C
Now let's calculate the charge on the planet with E = 222 N / c and radius
r = 0.6 r_ Earth
r = 0.6 6.37 10⁶ = 3.822 10⁶ m
E = k q / r²
q = E r² / k
q =
q = 3.6 10⁵ C
