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N76 [4]
3 years ago
10

Scientific notation of 86400

Physics
2 answers:
Diano4ka-milaya [45]3 years ago
4 0
86400 scientific notation is equal to 8.64×10^4 . it also write as 8.64×10000
Mandarinka [93]3 years ago
3 0
8.64×10^4

this is 86400 in scientific notation

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An object will have the same mass and weight on the moon as it has on Earth.
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Answer: A: false

Explanation:

And object will weigh less on the moon because the moons gravity is weaker than Earths gravity.

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2 years ago
Write a speech about bringing back fidget toys because they're banned in school
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I believe that fidget toys should not be brought back in school, reason being is because fidget spinners were originally made for students with example: Autism . Who actually needed them. Now that people who don't need them are buying them and playing with them in the classroom, it causes a complete distraction and is not being used for its original purpose whatsoever .
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3 years ago
Energy Transformation
Serjik [45]

Answer:

<em>K =400000 J</em>

Explanation:

<u>Kinetic Energy</u>

Is the energy an object has due to its state of motion. It's proportional to the square of the speed.

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\displaystyle K=\frac{1}{2}mv^2

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3 0
3 years ago
An object of mass 2.0 kg is attached to the top of a vertical spring that is anchored to the floor. The unstressed length of the
poizon [28]

Answer:

The value is A  =  0.014 \  m

Explanation:

From the question we are told that

    The mass of the object is  m  =  2.0 \  kg

    The unstressed length of the string is  l  =  0.08 \  m

    The length of the spring when it is  at equilibrium is  l_e = 5.9 \  cm  =  0.059 \  m

      The initial speed (maximum speed)of the spring when given a downward blow v  =  0.30 \  m/s

Generally the maximum speed  of the spring  is mathematically represented as

           u =  A *  w

Here A is maximum height above the floor (i.e the maximum amplitude)

            and w is the angular frequency which is mathematically represented as

       w = \sqrt{\frac{k}{m} }

So

        u =  A *   \sqrt{\frac{k}{m} }

=>      A  =  u *   \sqrt{\frac{m}{k} }

Gnerally the length of the compression(Here an assumption that the spring was compressed to the ground by the hammer is made) by the hammer is mathematically represented as

           b  =  l -l_e

=>         b  = 0.08 - 0.05 9

=>         b  = 0.021 \  m

Generally at equilibrium position the net force acting on the spring is  

            k *  b  -  mg  =  0

=>         k *  0.021   -   2 * 9.8  =  0

=>        k =  933 \  N/m

So

            A  =  0.30  *   \sqrt{\frac{2}{933} }

=>          A  =  0.014 \  m

8 0
2 years ago
A 878-kg (1940 lb) dragster, starting from rest, attains a speed of 25.9 m/s (57.9 mph) in 0.62 s. (a) Find the average accelera
salantis [7]

Answer:

41.8m/s^2

Explanation:

Since the dragster starts from rest, initial velocity (u) = 0m/s, final velocity (v) = 25.9m/s, time (t) = 0.62s

From the equations of motion, v = u + at

a = (v - u)/t = (25.9 - 0)/0.62 = 25.9/0.62 = 41.8m/s^2

7 0
2 years ago
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