Answer:
x = 5.29 m
Explanation:
given,
weight of stretch = 37 N
left-hand spring constant (k₁)= 2.7 N/cm
right hand spring constant(k₂)= 4.3 N/ cm
spring are connected in parallel
F = F₁ + F₂
F = k₁x + k₂x
F = (k₁+ k₂)x
37= (4.3+ 2.7)x
7 x = 37
x = 5.29 m
Answer:
See attached file :)
Hope this helps!
All the love, Ya boi Fraser :)
Answer:
Work done,W= 250J
Displacement , s = 60
We know that, Work done = Force x displacement
i.e , W = Fxs
250 J = F x 60m
F = 250/60
=4.16 N
Hence , 4.16 N of Force is applied on the body.
Measure the length of one side and then cube the answer. So if x represents the measurement of one side, x³ will give you the volume.
Answer:
The net acceleration of the boat is approximately 6.12 m/s² downwards
Explanation:
The buoyant or lifting force applied to the boat = 790 N
The mass of the boat lifted by the buoyant force = 214 kg
The force applied to a body is defined as the product of the mass and the acceleration of the body. Therefore, the buoyant force, F, acting on the boat can be presented as follows;
Fₐ = F - W
The weight of the boat = 214 × 9.81 = 2099.34 N
Therefore;
Fₐ = 790 - 2099.34 = -1309.34 N
Fₐ = Mass of the boat × The acceleration of the boat
Given that the buoyant force, Fₐ, is the net force acting on the boat, we have;
F = Mass of the boat × The net acceleration of the boat
F = -1309.34 N = 214 kg × The net acceleration of the boat
∴ The net acceleration of the boat = -1309.34 N/(214 kg) ≈ -6.12 m/s²
The net acceleration of the boat ≈ 6.12 m/s² downwards
