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3 years ago

When a heart artery is clogged and the heart muscle dies, the condition is _______________ ischemia.

Physics

2 answers:

Zolol [24]3 years ago

5 0

Angina or heart attack

3241004551 [841]3 years ago

3 0

the answer is Cardiac ishemia

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A man can jump 1.5 m on earth. calculate the approximate

Olegator [25]

Answer:

18 m

Explanation:

G = Gravitational constant

m = Mass of planet = $\rho V$

$\rho$ = Density of planet

V = Volume of planet assuming it is a sphere = $\dfrac{4}{3}\pi r^3$

r = Radius of planet

Acceleration due to gravity on a planet is given by

$g=\dfrac{Gm}{r^2}\\\Rightarrow g=\dfrac{G\rho V}{r^2}\\\Rightarrow g=\dfrac{G\rho \dfrac{4}{3}\pi r^3}{r^2}\\\Rightarrow g=\dfrac{4G\rho\pi r}{3}$

So,

$g\propto \rho r$

Density of other planet = $\rho_p=\dfrac{1}{4}\rho_e$

Radius of other planet = $r_p=\dfrac{1}{3}r_e$

$\dfrac{g_e}{g_p}=\dfrac{\rho_e r_e}{\rho_p r_p}\\\Rightarrow \dfrac{g_e}{g_p}=\dfrac{\rho_e r_e}{\dfrac{1}{4}\rho_e\times \dfrac{1}{3}r_e}\\\Rightarrow \dfrac{g_e}{g_p}=12\\\Rightarrow g_p=\dfrac{g_e}{12}\\\Rightarrow g_p=\dfrac{9.8}{12}$

Since the person is jumping up the acceleration due to gravity will be negative.

From kinematic equations we have

$v^2-u^2=2g_es\\\Rightarrow u^2=v^2-2g_es\\\Rightarrow u^2=0-2\times -9.8\times 1.5\\\Rightarrow u^2=2\times 9.8\times 1.5$

On the other planet

$v^2-u^2=2g_ps\\\Rightarrow s=\dfrac{v^2-u^2}{2g_p}\\\Rightarrow s=\dfrac{0-(2\times 9.8\times 1.5)}{2\times -\dfrac{9.8}{12}}\\\Rightarrow s=18\ \text{m}$

The man can jump a height of 18 m on the other planet.

5 0

3 years ago

Match the following list of key words with their definitions

Korvikt [17]

Question 1 :

1. VELOCITY

2. SPEED

3. NEWTON

4. MOMENTUM

5. MASS

Question 2

1. FORCE

2. FRICTION

3. GRAVITY

4. ELECTROAGNETIC FORCE

5. ACCELERATION

6 0

2 years ago

A vector is 14.4 m long and

MaRussiya [10]

Answer:

Explanation:

The x-component is found in the magnitude of the vector times the cosine of the angle.

$A_x=14.4cos133$ and, to 3 sig dig,

$A_x=-9.82m$

3 0

3 years ago

6th grade science !!!!!!!!!!!!!!!

posledela

Answer:

Explanation:

5 0

3 years ago

a man hits a golf ball (0.2kg) which accelerates at a rate of 20 m/s what amount of force acted on the ball

MAVERICK [17]

The ball only accelerates during the brief time that the club is in contact
with it. After it leaves the club face, it takes off at a constant speed.

If it accelerates at 20 m/s² during the hit, then

Force = (mass) x (acceleration) = (0.2kg) x (20 m/s²) = <em>4 newtons</em> .

8 0

3 years ago

Read 2 more answers