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3 years ago

Balance this equation Hgo —> Hg + O2

Chemistry

1 answer:

Nesterboy [21]3 years ago

6 0

Answer:

2Hgo —>2Hg + O2

Explanation:

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You believe you have cracked a secret code that uses elemental symbols to spell words. The code uses numbers to designate the el

Stells [14]

Explanation:

Atomic numbers for neutral atoms are the same as the number of electrons. The number of electrons are used in writing the subshell notation where we can see the highest princpal quantum number(n).

In order to solve this problem, a good knowledge of the periodic table and shell notation is required.

For example;

Given a number 5;

We know the number is made of both the atomic number of the element and the highest quantum number.

It is easier for us to know the highest quantum number from the shell notation:

shell notation 1s²2s²2p¹

highest principal quantum number is 2

We are left with atomic number 5-2, which is 3

The element is therefore Li.

Part A. 5, 30, 58, 56, 99, 79, 19, 98, 9

Li Fe I Sb U Ta S Pa N

Part B. 9, 99, 30, 95, 19, 47, 79

N U Fe Ra S Mo Ta

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3 years ago

What are the rows of the periodic table of the elements also called?

lesya [120]

The rows are called Periods.

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3 years ago

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What effect does a catalyst have on a system in equilibrium?

irina1246 [14]

A catalyst is when a chemical reaction occurs faster than normal.

The system is unaffected during a catalyst because both forward and reverse reactions are affected, meaning that quilibrium will occur faster nothing will change.

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4. A student purified a 500-mg sample of phthalic acid by recrystallization from water. The published solubility of phthalic aci

kupik [55]

Answer:

2.77 mL of boiling water is the minimum amount which will dissolve 500 mg of phthalic acid.

Explanation:

We know from the problem that 18 g of phthalic acid are dissolved in 100 mL of water at 99 °C.

Now we devise the following reasoning:

If 18 g of phthalic acid are dissolved in 100 mL of water at 99 °C

Then 0.5 g of phthalic acid are dissolved in X mL of water at 99 °C

X = (0.5 × 100) / 18 = 2.77 mL of water

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3 years ago

You are given an unknown gaseous binary compound (that is, a compound consisting of two different elements). when 10.0 g of the

Luda [366]

Answer is: a possible identity for the unknown compound is C₃H₈.

m(binary compound) = 10.0 g.

m(H₂O) = 16.3 g; mass of water.

M(O₂) = 32 g/mol; molar mass of oxygen.

M(binary compound) = 1.38 · 32 g/mol.

M(binary compound) = 44.16 g/mol.

n(binary compound) = 10 g ÷ 44.16 g/mol.

n(binary compound) = 0.225 mol; amount of substance.

n(H₂O) = 16.3 g ÷ 18 g/mol.

n(H₂O) = 0.9 mol; amount of water.

m(H₂O) : n(binary compound) = 0.9 mol ÷ 0.225 mol.

m(H₂O) : n(binary compound) = 4 : 1.

Unknown cpmpound has 4 times more hydrogen than water, it has 8 hydrogen atoms.

Second element in compound is carbon:

M(X) = 44.16 g/mol - 8 · 1.01 g/mol.

M(X) = 36.08 g/mol ÷ 3.

M(C) = 12.01 g/mol.

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3 years ago