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miss Akunina [59]
3 years ago
9

How many moles of hypomanganous acid. H3 MnO4, are contained in 22.912 g?

Chemistry
1 answer:
gregori [183]3 years ago
6 0

Answer:

0.188mol

Explanation:

Using the formula;

mole = mass/molar mass

Molar mass of hypomanganous acid. (H3MnO4) = 1(3) + 55 + 16(4)

= 3 + 55 + 64

= 122g/mol

According to this question, there are 22.912g of H3MnO4

mole = 22.912g ÷ 122g/mol

mole = 0.188mol

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Step2247 [10]

Answer:

m_{H_2O}=9.24gH_2O

Explanation:

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Determine the concentration of hydronium and hydroxide ions in a solution that has a pH of 1.6.
Veronika [31]

Answer:

The answer to your question is [H₃O⁺] = 0.025   [OH⁻] = 3.98 x 10⁻¹³

Explanation:

Data

[H⁺] = ?

[OH⁻] = ?

pH = 1.6

Process

Use the pH formula to calculate the [H₃O⁺], then calculate the pOH and with this value, calculate the [OH⁻].

pH formula

pH = -log[H₃O⁺]

-Substitution

1.6 = -log[H₃O⁺]

-Simplification

[H₃O⁺] = antilog (-1,6)

-Result

[H₃O⁺] = 0.025

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pOH = 14 - pH

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pOH = 14 - 1.6

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pOH = 12.4

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-Result

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