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miss Akunina [59]
3 years ago
9

How many moles of hypomanganous acid. H3 MnO4, are contained in 22.912 g?

Chemistry
1 answer:
gregori [183]3 years ago
6 0

Answer:

0.188mol

Explanation:

Using the formula;

mole = mass/molar mass

Molar mass of hypomanganous acid. (H3MnO4) = 1(3) + 55 + 16(4)

= 3 + 55 + 64

= 122g/mol

According to this question, there are 22.912g of H3MnO4

mole = 22.912g ÷ 122g/mol

mole = 0.188mol

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Answer:

The calculated concentration of sodium thiosulphate solution will be less than the actual value.

Explanation:

When IO3^2- solution is added to KI solution, I2 gas is released ,then sulphuric acid is now added to facilitate reduction. In order to prevent the escape of iodine (I2) gas ,the solution must immediately be titrated with thiosulphate.

If the solution is not immediately titrated with thiosulphate, the concentration of iodine available in the system decreases. When this occurs, it will also cause a decrease in the amount of iodine available to react with thiosulphate thus decreasing the concentration of thiosulphate obtained from calculation

5 0
3 years ago
Calculate the concentration imports per million ppm of DDT if a sample size of 5000 g contained 0.10 g DDT
nevsk [136]

Answer:

20ppm

Explanation:

parts per million are defined as the mass of solute in mg (In this case, mass of DDT) per kg of sample.

To solve this question we must find the mass of DDT in mg and the mass of sample in kg:

<em>Mass DDT:</em>

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100mg / 5kg =

<h3>20ppm</h3>
3 0
3 years ago
Importance of pH value in daily life
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dimaraw [331]
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A radioisotope decays to give an alpha particle andPb-208.
oee [108]

<u>Answer:</u> The original element is _{84}^{212}\textrm{Po}

<u>Explanation:</u>

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The released alpha particle is also known as helium nucleus.

_Z^A\textrm{X}\rightarrow _{Z-2}^{A-4}\textrm{Y}+_2^4\alpha

For the given alpha decay process of an isotope:

^{Z}_{A}\textrm{X}\rightarrow ^{208}_{82}\textrm{Pb}+_2^4\alpha

<u>To calculate A:</u>

Total mass on reactant side = total mass on product side

A = 208 + 4

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<u>To calculate Z:</u>

Total atomic number on reactant side = total atomic number on product side

Z = 82 + 2

Z = 84

The isotopic symbol of unknown element is _{84}^{212}\textrm{Po}

Hence, the original element is _{84}^{212}\textrm{Po}

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3 years ago
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