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kap26 [50]
2 years ago
6

The solubility of nitrogen gas at 25 ◦C and 1 atm is 6.8×10−4 mol/L. If the partial pressure of nitrogen gas in air is 0.76 atm,

what is the concentration (molarity) of dissolved nitrogen?
Chemistry
1 answer:
iris [78.8K]2 years ago
5 0

Answer:

Concentration of dissolved nitrogen = 5.2 × 10⁻⁴ mol/L

Explanation:

More the pressure of the gas, more will be its solubility.

So, for two different pressure, the relation between them is shown below as:-

\frac {P_1}{C_1}=\frac {P_2}{C_2}

Given ,  

P₁ = 1 atm

P₂ = 0.76 atm

C₁ = 6.8 × 10⁻⁴ mol/L

C₂ = ?

Using above equation as:

\frac{1\ atm}{6.8\times 10^{-4}\ mol/L}=\frac{0.76\ atm}{C_2}

C_2=\frac{0.76\times 6.8\times 10^{-4}}{1}\ mol/L

<u>Concentration of dissolved nitrogen = 5.2 × 10⁻⁴ mol/L</u>

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<u>Answer:</u> 18 moles of H_2O will be produced.

<u>Explanation:</u>

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To study the organism.

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3 years ago
The burning of ethane produces both co2 and H2O. if 400 ml of CO2 is produced at 30°C and 740 torr, what volume of water vapor w
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The volume of water vapour would be produced at 19°C and 780 torr is 548.5mL.

If 400 ml of CO2 is produced at 30°C at 740 torr, then number of moles can be calculated as:

By using ideal gas equation:

P1V1 = N1R1T1

P1 = pressure = 740torr

V1 = 400 ml = volume of CO2

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T = 273+30 = 303 k

740×400 = N1×8.314×303

N1 = (740×400) /(8.314×303) =117.5.

Chemical equation

C2H6 ---- 2CO2 + 3H2O.

As we noticed from the equation that

2 moles of CO2 = 3 moles of H2O

1 moles of CO2 × 1 moles of H2O

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P2V2 = N2RT2

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learn more about ideal gas equation:

brainly.com/question/12242461

#SPJ4

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Calculate to three significant digits the density of dinitrogen monoxide gas at exactly and exactly . You can assume dinitrogen
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Answer:

see explanation below

Explanation:

You miss the part of the temperature and pressure. According to what I found this is held under 30 °C (or 303 K) and 1 atm.

The problem states that we can treat this gas as an ideal gas, therefore, we can use the equation of an ideal gas which is:

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Now, the density (d) is calculated as:

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d = 1 * 44 / 0.082 * 303

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