What is the question is it a fill in the blank multiple choice?
<u>Answer:</u> 18 moles of
will be produced.
<u>Explanation:</u>
We are given:
Moles of ammonia = 12 moles
The given chemical equation follows:

By the stoichiometry of the reaction:
4 moles of ammonia produces 6 moles of water
So, 12 moles of ammonia will produce =
of water
Hence, 18 moles of
will be produced.
Answer:
To study the organism.
Explanation:
When paleontologists find only partial remains of some organism so they study it in order to find the characteristic of the organism and find out the history of earth. paleontologists are the scientists who study fossils of plants and animals to study the history of earth so we can say that paleontologists study the partial remains in order to study the history of earth.
The volume of water vapour would be produced at 19°C and 780 torr is 548.5mL.
If 400 ml of CO2 is produced at 30°C at 740 torr, then number of moles can be calculated as:
By using ideal gas equation:
P1V1 = N1R1T1
P1 = pressure = 740torr
V1 = 400 ml = volume of CO2
R = Gas constant = 8.314
T = 273+30 = 303 k
740×400 = N1×8.314×303
N1 = (740×400) /(8.314×303) =117.5.
Chemical equation
C2H6 ---- 2CO2 + 3H2O.
As we noticed from the equation that
2 moles of CO2 = 3 moles of H2O
1 moles of CO2 × 1 moles of H2O
Then N2 = 117.5 moles of CO2 = 3/2 × 117.5 moles of H2O
By using ideal gas equation:
P2V2 = N2RT2
V2 = 3/2 × 117.5 × 8.314 × 292/ 780
= 548.5ml.
Thus, we found that the volume of water vapour would be produced at 19°C and 780 torr is 548.5mL.
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Answer:
see explanation below
Explanation:
You miss the part of the temperature and pressure. According to what I found this is held under 30 °C (or 303 K) and 1 atm.
The problem states that we can treat this gas as an ideal gas, therefore, we can use the equation of an ideal gas which is:
PV = nRT (1)
Now, the density (d) is calculated as:
d = m/V (2)
We can rewrite (2) in function of mass of volume so:
m = d*V (3)
Now, the moles (n) of (1) can be calculated like this:
n = m /MM (4)
If we replace it in (1) and then, (3) into this we have the following:
PV = mRT/MM ----> replacing (3):
PV = dVRT/MM ----> V cancels out so finallly:
P = dRT/MM
d = P * MM / RT (5)
The molar mass of N2O is 44 g/mol So, replacing all the data we have:
d = 1 * 44 / 0.082 * 303
d = 1.77 g/L