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2 years ago

11

In _____________ compression design the signal is split at the input, and one signal is used to compress the other slightly dela

yed split signal.

1 answer:

Inessa05 [86]2 years ago

7 0

Answer:

Feed Forward

Explanation:

In FEED FORWARD compression design the signal is split at the input, and one signal is used to compress the other slightly delayed split signal.

I hope it helps! Have a great day!

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Calculate the areas under the stress-strain curve (toughness) for the materials shown in Fig. below, (a) plot them as a

defon

Answer:

Explanation:

Wow

5 0

3 years ago

Do not use C++ pointers (this is not a topic of this course).

noname [10]

The program is an illustration of functions in C++

C++ functions are collection of named program statements that are executed when called

<h3>The C++ program</h3>

The program in C++, where comments are used to explain each action is as follows:

#include <iostream>

#include <cmath>

using namespace std;

//This defines the boolean method

bool isoscelesTriangleHeightAndArea(double base, double hypotenuse, double height, double area) {

//This checks for invalid base and height

if(base < 0 || hypotenuse < 0){

return false;

}

//This returns true if base and height are valid

return true;

}

//The main begins here

int main(){

//This initializes the variables

double base, hypotenuse, height, area;

//This gets input for base and hypotenuse

cout<<"Base: "; cin>>base;

cout<<"Hypotenuse: "; cin>>hypotenuse;

//The calls the boolean method

bool success = isoscelesTriangleHeightAndArea(base, hypotenuse, height, area);

//If success is True

while (success){

//This calculates height

height = sqrt(hypotenuse*hypotenuse - (base/2) * (base/2));

//This calculates area

area = 0.5 * base * height;

//This prints height

cout << "Triangle height is " << height << endl;

//This prints area

cout << "Triangle area is " << area << endl;

//This gets input for base and hypotenuse

cout<<"Base: "; cin>>base;

cout<<"Hypotenuse: "; cin>>hypotenuse;

bool success = isoscelesTriangleHeightAndArea(base, hypotenuse, height, area);

}

cout << "Invalid Input!" << endl;

}

Read more about C++ programs at:

brainly.com/question/24833629

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4 0

2 years ago

The three sub regions of South America are the Andes Mountains, the Amazon Rainforest, and the Eastern Highlands. The Atacama De

Leto [7]

Answer:

<:

Explanation:

8 0

3 years ago

Read 2 more answers

Find the time-domain sinusoid for the following phasors:_________

sattari [20]

<u>Answer</u>:

a. r(t) = 6.40 cos (ωt + 38.66°) units

b. r(t) = 6.40 cos (ωt - 38.66°) units

c. r(t) = 6.40 cos (ωt - 38.66°) units

d. r(t) = 6.40 cos (ωt + 38.66°) units

<u>Explanation</u>:

To find the time-domain sinusoid for a phasor, given as a + bj, we follow the following steps:

(i) Convert the phasor to polar form. The polar form is written as;

r∠Ф

Where;

r = magnitude of the phasor = $\sqrt{a^2 + b^2}$

Ф = direction = tan⁻¹ ( $\frac{b}{a}$ )

(ii) Use the magnitude (r) and direction (Φ) from the polar form to get the general form of the time-domain sinusoid (r(t)) as follows:

r(t) = r cos (ωt + Φ)

Where;

ω = angular frequency of the sinusoid

Φ = phase angle of the sinusoid

(a) 5 + j4

<em>(i) convert to polar form</em>

r = $\sqrt{5^2 + 4^2}$

r = $\sqrt{25 + 16}$

r = $\sqrt{41}$

r = 6.40

Φ = tan⁻¹ ( $\frac{4}{5}$ )

Φ = tan⁻¹ (0.8)

Φ = 38.66°

5 + j4 = 6.40∠38.66°

(ii) <em>Use the magnitude (r) and direction (Φ) from the polar form to get the general form of the time-domain sinusoid</em>

r(t) = 6.40 cos (ωt + 38.66°)

(b) 5 - j4

<em>(i) convert to polar form</em>

r = $\sqrt{5^2 + (-4)^2}$

r = $\sqrt{25 + 16}$

r = $\sqrt{41}$

r = 6.40

Φ = tan⁻¹ ( $\frac{-4}{5}$ )

Φ = tan⁻¹ (-0.8)

Φ = -38.66°

5 - j4 = 6.40∠-38.66°

(ii) <em>Use the magnitude (r) and direction (Φ) from the polar form to get the general form of the time-domain sinusoid</em>

r(t) = 6.40 cos (ωt - 38.66°)

(c) -5 + j4

<em>(i) convert to polar form</em>

r = $\sqrt{(-5)^2 + 4^2}$

r = $\sqrt{25 + 16}$

r = $\sqrt{41}$

r = 6.40

Φ = tan⁻¹ ( $\frac{4}{-5}$ )

Φ = tan⁻¹ (-0.8)

Φ = -38.66°

-5 + j4 = 6.40∠-38.66°

(ii) <em>Use the magnitude (r) and direction (Φ) from the polar form to get the general form of the time-domain sinusoid</em>

r(t) = 6.40 cos (ωt - 38.66°)

(d) -5 - j4

<em>(i) convert to polar form</em>

r = $\sqrt{(-5)^2 + (-4)^2}$

r = $\sqrt{25 + 16}$

r = $\sqrt{41}$

r = 6.40

Φ = tan⁻¹ ( $\frac{-4}{-5}$ )

Φ = tan⁻¹ (0.8)

Φ = 38.66°

-5 - j4 = 6.40∠38.66°

(ii) <em>Use the magnitude (r) and direction (Φ) from the polar form to get the general form of the time-domain sinusoid</em>

r(t) = 6.40 cos (ωt + 38.66°)

3 0

3 years ago

From the hazards blisted below, determine which could require foot protection

MrRa [10]

Foot protection could be required with Sharps, Slippery areas, Hazardous liquids,and Falling objects.

Hope this helps!!

8 0

3 years ago