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motikmotik
1 year ago
9

The mineral galena is composed of lead(II) sulfide and has an average density of 7.46 g/cm³.

Chemistry
1 answer:
postnew [5]1 year ago
7 0

The mineral galena is composed of lead(II) sulfide and has an average density of 7.46 g/cm³. Moles of lead(II) sulfide in 1.00 ft³ of galena are 883 mol PbS.

<h3>What is moles of compound?</h3>

A very large number of molecules, atoms, or other particles are referred to as a "mole," which is a unit of measurement in chemistry. The number of moles in one unit is 6.02214 x 1023, and it is known as Avogadro's Number. These figures are crucial in providing information on the quantity of the constituent elements. A mole of a substance might be as little as a few grams or as much as hundreds of grams.

One mole (or formula unit) of a chemical is equal to 6.022 x 10²³ molecules (ionic). A chemical's molar mass represents the mass of 1 mole of that substance. To put it another way, it tells you how many grams there are in a chemical per mole.

To learn more about moles visit:

brainly.com/question/26416088

#SPJ4

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A sample of a compound is decomposed in the laboratory and produces 330 g carbon, 69.5 g hydrogen, and 220.2 g oxygen. Calculate
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Answer: Empirical formula is C_2H_5O

Explanation: We are given the masses of elements present in a sample of compound. To evaluate empirical formula, we will be following some steps.

<u>Step 1 :</u> Converting each of the given masses into their moles by dividing them by Molar masses.

Moles=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of Carbon = 12.0 g/mol

Molar mass of Hydrogen = 1.0 g/mol

Molar mass of Oxygen = 16.0 g/mol

Moles of Carbon = \frac{330g}{12g/mol}=27.5moles

Moles of Hydrogen = \frac{69.5g}{1g/mol}=69.5moles

Moles of Oxygen = \frac{220.2g}{16g/mol}=13.76moles

<u>Step 2: </u>Dividing each mole value by the smallest number of moles calculated above and rounding it off to the nearest whole number value

Smallest number of moles = 13.76 moles

\text{Mole ratio of Carbon}=\frac{27.5moles}{13.76moles}=1.99\approx 2

\text{Mole ratio of Hydrogen}=\frac{69.5moles}{13.76moles}=5.05\approx 5

\text{Mole ratio of Oxygen}=\frac{13.76moles}{13.76moles}=1

<u>Step 3:</u> Now, the moles ratio of the elements are represented by the subscripts in the empirical formula

Empirical formula becomes = C_2H_5O

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If 54.9 L of an ideal gas is cooled from 64 degrees C to 7 degrees C, what will the volume of the gas become?
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