Answer:
Kb for CH₃NH₂ (methylamine) is 4.4 × 10⁻⁴
Hope that helps.
Answer:
1. 12.09 mole
2. 600.47g
Explanation:
First, we'll begin by writing a balanced equation for the reaction. The balance equation is given below:
2KClO3(s) —> 2KCl(s)+ 3O2(g)
1. From the balanced equation above,
2 moles of potassium chlorate (KClO3) produced 3 moles of oxygen (O2) .
Therefore, 8.06 moles of potassium chlorate (KClO3) will produce = (8.06x3)/2 = 12.09 moles of oxygen (O2).
From the calculations above, 8.06 moles of potassium chlorate (KClO3) will produce 12.09 moles of oxygen (O2)
2. From the balanced equation above,
2 moles of potassium chlorate (KClO3) produced 2 moles of potassium chloride (KCl).
Therefore, 8.06 moles of potassium chlorate (KClO3) will also produce 8.06 moles of potassium chloride (KCl).
Now, we need to convert 8.06 moles of potassium chloride (KCl) to grams in order to obtain the desired result. This is illustrated below:
Molar Mass of KCl = 39 + 35.5 = 74.5g/mol
Mole of KCl = 8.06 moles
Mass of KCl =?
Mass = number of mole x molar Mass
Mass of KCl = 8.06 x 74.5
Mass of KCl = 600.47g
Therefore, 8.06 moles of potassium chloride (KCl) will produce 600.47g of potassium chloride (KCl)
Answer:
They've all been formed by water erosion
Explanation:
Water erosion is referred to as the detachment and transport of materials in the form of soil particles or movements of soil mass from one location to another on the action of rain and runoff. Its negative effects are associated with delicate equilibrium regions whose soil is very susceptible to erosion. The lack of vegetation cover, together with the characteristics of the precipitation, are factors that interfere in this process with intensity and frequency. In addition to causing soil loss, water erosion is one of the main elements forming floodplains, sandbars and river deltas.
Answer:
When heat gets transferred through electromagnetic waves that move through space
.
Explanation:
Radiation is the propagation of energy in the form of electromagnetic waves or subatomic particles through a vacuum or a material medium.
Answer:
3I^-/I3^-//Tl3^+//Tl^+
Explanation:
Based on the given reduction potentials, the half reaction equation having greater positive value will be the cathode while the half reaction equation having less positive reduction potential will be the anode.
This implies that this equation:
Tl3+ (aq) + 2e- → Tl+ (aq) ξo = 1.24 occurs at the cathode
While:
3 I- (aq) → I3- (aq) + 2e- ξo = -0.55 occurs at the anode
Cell notation,
Anode//cathode
Hence for this system under consideration:
3I^-/I3^-//Tl3^+//Tl^+