B because those are the elements
What are you looking for? bc i can’t see what you are asking
These are called subscript number.
That is the number below the normal line of test are called subscript number.
This number indicate the indicate the number of atoms of the element present in the chemical formula.
In both of these C₆H₁₂O₆ and H₂O, the number written below the line of the text are called subscript numbers.
Answer:
The percentage by mass of benzene in the solution is approximately 0.2%
Explanation:
The given parameters are;
The mass of the benzene solute dissolved in the gasoline solvent, m₁ = 1.56 g
The total volume of the benzene gasoline solution made, V = 998.44 mL
The density of gasoline, ρ = 0.7489 g/mL
Mass, m = Density, ρ × Volume, V
∴ The mass of gasoline in the 998.44 mL, solution = 0.7489 g/mL × 998.44 mL = 747.731716 g
The total mass of the solution = The mass of the benzene in the solution + The mass of the gasoline in the solution
∴ The total mass of the solution = 747.731716 g + 1.5 g = 749.231716 g
![The \ percentage \ by \ mass = \dfrac{The \ mass \ of \ a \ fraction}{(The \ mass \ of \ the \ total \ solution)} \times 100](https://tex.z-dn.net/?f=The%20%5C%20percentage%20%5C%20%20by%20%5C%20%20mass%20%3D%20%5Cdfrac%7BThe%20%20%5C%20%20mass%20%5C%20%20%20of%20%5C%20%20%20a%20%20%5C%20%20fraction%7D%7B%28The%20%20%5C%20%20mass%20%20%5C%20%20of%20%20%5C%20%20the%20%20%5C%20%20total%20%20%5C%20%20solution%29%7D%20%5Ctimes%20%20100)
The percentage by mass of benzene in the solution = (1.5 g/749.231716 g)×100 ≈ 0.2% by mass.