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Mrac [35]
3 years ago
11

When a 0.1-kilogram pendulum bob reaches the top of its swing, how much kinetic energy does it have?

Physics
1 answer:
zvonat [6]3 years ago
7 0
When ANY pendulum bob reaches the top of its swing,
it stops momentarily and then begins to drop.  At the instant
when it stops, its kinetic energy is zero.
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What is the relationship between the atoms of elements,its isotopes and its ions
klasskru [66]
An element refers to a collection of atoms having the same number of protons and electrons (an atomic number). In each element there is a different atomic number due to a different amount of protons in the nucleus.

An isotope is a variation of an element that contains a different number of neutrons, therefore adding weight to the atom.

An ion is a charged atom, and its charge shows how many electrons it needs to gain or lose in order to become stable.
6 0
4 years ago
In which states of matter will a substance have a fixed volume?
NISA [10]

Answer:

A. liquid and solid

Explanation:

7 0
3 years ago
A car start from rest and reached with a speed of 20m/s in 9seconds calculate the acceleration of the car and calculate the disp
Snezhnost [94]

Hi there!

Acceleration:

a = Δv / Δt, so:

a = 20/9 ≈ 2.22 m/s²

Displacement:

We can use the equation Δd = v₀t + 1/2at² to solve. (Initial velocity is 0).

Δd = 1/2at²

Plug in the acceleration and time:

Δd = 1/2(2.22)(9)² ≈ 89.91 m

5 0
3 years ago
A man pushes a lawn mower on a level lawn with a force of 186.5 N. If 3.8% of this
Paladinen [302]

Explanation:

The force is 186.5 N.  3.8% of the force is directed downward.  So the vertical component of the force is:

Fᵧ = 0.038 (186.5 N)

Fᵧ = 7.087 N

The horizontal component is found with Pythagorean theorem:

F² = Fₓ² + Fᵧ²

(186.5 N)² = Fₓ² + (7.087 N)²

Fₓ = 186.4 N

So the work done is:

W = Fd

W = (186.4 N) (7.4 m)

W = 1379 J

Round as needed.

4 0
3 years ago
g Drop the object again and carefully observe its motion after it hits the ground (it should bounce). (Consider only the first b
Anestetic [448]

Answer:

a) quantity to be measured is the height to which the body rises

b) weighing the body , rule or fixed tape measure

c)   Em₁ = m g h

d) deformation of the body or it is transformed into heat during the crash

Explanation:

In this exercise of falling and rebounding a body, we must know the speed of the body when it reaches the ground, which can be calculated using the conservation of energy, since the height where it was released is known.

a) What quantities must you know to calculate the energy after the bounce?

The quantity to be measured is the height to which the body rises, we assume negligible air resistance.

So let's use the conservation of energy

starting point. Soil

          Em₀ = K = ½ m v²

final point. Higher

          Em_f = U = mg h

         Em₀ = Em_f

         Em₀ = m g h₀

b) to have the measurements, we begin by weighing the body and calculating its mass, the height was measured with a rule or fixed tape measure and seeing how far the body rises.

c) We use conservation of energy

starting point. Soil

          Em₁ = K = ½ m v²

final point. Higher

          Em_f = U = mg h

         Em₁ = Em_f

         Em₁ = m g h

d) to determine if the energy is conserved, the arrival energy and the output energy must be compared.

There are two possibilities.

* that have been equal therefore energy is conserved

* that have been different (most likely) therefore the energy of the rebound is less than the initial energy, it cannot be stored in the possible deformation of the body or it is transformed into heat during the crash

7 0
3 years ago
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