0.04m²
Explanation:
Given parameters:
Pressure = 250000Pa
Weight = 40000N
Unknown:
Area of each foot = ?
Solution:
Pressure is the force exerted per unit area of a body
Pressure = 
To find the area;
Area = 
Area = 
= 0.16m²
The force exerted by all the four feet is 0.16m²
the area of each feet = 
= 0.04m²
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Answer:
T_ww = 43,23°C
Explanation:
To solve this question, we use energy balance and we state that the energy that enters the systems equals the energy that leaves the system plus losses. Mathematically, we will have that:
E_in=E_out+E_loss
The energy associated to a current of fluid can be defined as:
E=m*C_p*T_f
So, applying the energy balance to the system described:
m_CW*C_p*T_CW+m_HW*C_p*T_HW=m_WW*C_p*T_WW+E_loss
Replacing the values given on the statement, we have:
1.0 kg/s*4,18 kJ/(kg°C)*25°C+0.8 kg/s*4,18 kJ/(kg°C)*75°C=1.8 kg/s*4,18 kJ/(kg°C)*T_WW+30 kJ/s
Solving for the temperature Tww, we have:
(1.0 kg/s*4,18 kJ/(kg°C)*25°C+0.8 kg/s*4,18 kJ/(kg°C)*75°C-30 kJ/s)/(1.8 kg/s*4,18 kJ/(kg°C))=T_WW
T_WW=43,23 °C
Have a nice day! :D
Do you have a picture then I could determine 1 millimeter
Answer:
0.96 kWh
Explanation:
First of all, we can find the power of the appliance using the formula:
where
V = 120 V is the voltage of the source
I = 2 A is the current
Substituting,
Now we want to find the amount of energy used by the applied in a time of
t = 4 h
The amount of energy is given by
where
P = 0.24 kW
t = 4 g
Substituting,
Answer:
20%
Explanation:
Efficiency of an engine is a ratio in percentage of the work done to the energy intake of the engine.
η=(q₁-q₂)/q₁×100%
η is efficiency, q₁ is the energy intake, q₂ is energy wasted.
the information provided is:
energy intake = 400 j
work done = 80 j = (400-320) =q₁-q₂
energy wasted =320 j
η= 80/400×100%
=20%
