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Bad White [126]
1 year ago
12

An element has 2 neutrons, 2 electrons and 2 protons. Which element does this describe? Is it a neutral atom, isotope, or an ion

? What is the mass number? What is the net charge?
Chemistry
1 answer:
Y_Kistochka [10]1 year ago
4 0

Considering the definition of neutral atom, mass number and net charge, the element is a neutral atom, with a net charge equal to zero and a mass number of 4.

<h3>Neutral atom and ion</h3>

All atoms are made up of subatomic particles: protons and neutrons, which are part of their nucleus, and electrons, which revolve around them. Protons are positively charged, neutrons are neutrally charged, and electrons are negatively charged.

A neutral atom is one that has no electrical charge because it has the same number of protons and electrons.

In contrast, ions are atoms or groups of atoms that have an electrical charge and are formed by the gain or loss of electrons from the atom.

<h3>Mass number</h3>

The mass number tells us the total number of particles in the nucleus. That is, the mass number is the sum of the number of protons and the number of neutrons in the atomic nucleus:

Mass number = (number of protons) + (number of neutrons)

It is represented by the letter A.

<h3>Net charge</h3>

The net charge corresponds to the algebraic sum of all the charges that a atom possesses.

<h3>This case</h3>

In this case, an element has:

  • 2 neutrons.
  • 2 electrons.
  • 2 protons.

Then, the net charge is calculated as:

net charge= 2× 0 [charge of neutron] + 2× (+1) [charge of proton] + 2× (-1) [charge of electron]

<u><em>net charge= 0</em></u>

This element has no electrical charge, or net charge is zero. Then, the element is a neutral atom.

On the other hand, the mass number is the sum of the number of protons and the number of neutrons. So, in this case:

mass number= 2 protons + 2 neutrons

<u><em>mass number= 4</em></u>

Finally, the element is a neutral atom, with a net charge equal to zero and a mass number of 4.

Learn more about

neutral atom:

brainly.com/question/24652228

brainly.com/question/18242008

brainly.com/question/18330612

mass number:

brainly.com/question/1758023

brainly.com/question/5527493

net charge:

brainly.com/question/24752359

#SPJ1

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Varvara68 [4.7K]

Answer:

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Explanation:

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Third the triplet at 3.7 is indicative of being next to the halogen.  Hydrocarbons by themselves do not have peaks that far downfield meaning that its shift could only be explained by the chlorine being involved.  Also we know that this can't be next to the methyl group since its multiplicity is to low to be next to it.  

That leaves the multiplet at 1.75 being the hydrogens on the middle carbon which also makes sense since it is more downfield then the methyl group (due to being closer to the chlorine) but is not far enough downfield to say the chlorine is there.  It also makes sense that it is a multiple since it would be a hextet due to the adjacent 5 hydrogens which can't always be resolved.

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aluminum has a density or 2.7g/cm3. copper has a density of 8.96/cm3. which metal would you choose to build a model airplane?
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7 0
3 years ago
Consider the reaction: P4 + 6Cl2 = 4PCl3.
likoan [24]

Answer:

The answer to your question is below

Explanation:

Consider the reaction: P4 + 6Cl2 = 4PCl3.

a. How many grams of Cl2 are needed to react with 20.00 g of P4? ___68.7 g___________

                                P4      +      6Cl2      =      4PCl3

                          4(31) ---------- 12(35.5)

                         20     ----------    x

                    x = 20(12x35.5) / 4(31)

                   x = 8520 / 124

                   x = 68.7 g

b. You have 15.00 g. of P4 and 22.00 g. of Cl2, identify the limiting reactant and calculate the grams of PCl3 that can be produced as well as the grams of excess reactant remaining. LR____________ grams PCl3 _________ grams excess reactant ___________

                            P4      +      6Cl2      =      4PCl3

                       124g             426 g               4(31 + 3(35.5)) = 550g

                        15g               22g

I will use P4 to find the limiting reactant

                 

                     x = (15 x 426) / 124 = 51.5   The limiting reactant is Chlorine

                                                                  because we need 51.5 g and we only have 22g

Excess reactant

                 x = (22 x 124) / 426 = 6.4 g of P4

           Excess P4 = 15 g - 6.4 = 8.6 g of P4 in excess

Grams of PCl3 produced

                              426 g of Cl2 ----------------  550 g of PCl3

                                 22g of Cl2 ------------- -     x

            x = (22 x 550) / 426 = 28.4 g of PCl3

c. If the actual amount of PCl3 recovered is 16.25 g., what is the percent yield? ______________

   % yield = (16.25  - 28.4) / 28.4 x 100

  % yield = 42.8

d. Given 28.00 g. of P4 and 106.30 g. of Cl2, identify the limiting reactant and calculate how many grams of the excess reactant will remain after the reaction. LR ______________ grams excess reactant

Limiting reactant

                                   124g of P4  -------------      426 g  6Cl2

                                     28g           ---------------     x

x = (28 x 426) / 124

x = 96.2 g of Cl2 and we have 106.3 so Chlorine is the excess reactant and P4 is the limiting reactant.

Excess reactant = 106.3  - 96.2 = 10.1 g of Cl2 in excess

                   

                 

4 0
3 years ago
A student prepared a stock solution by dissolving 10.0 g of KOH in enough water to make 150. mL of solution. She then took 15.0
yanalaym [24]

Answer: The concentration of KOH for the final solution is 0.275 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n = moles of solute

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moles of solute =\frac{\text {given mass}}{\text {molar mass}}=\frac{10.0g}{56g/mol}=0.178moles

Now put all the given values in the formula of molality, we get

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According to the dilution law,

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where,

C_1 = molarity of stock solution = 1.19 M

V_1 = volume of stock solution = 15.0 ml

C_2 = molarity of diluted solution = ?

V_2 = volume of diluted solution = 65.0 ml

Putting in the values we get:

1.19\times 15.0=M_2\times 65.0

M_1=0.275M

Therefore, the concentration of KOH for the final solution is 0.275 M

5 0
3 years ago
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