Question

The initial concentration of acid ha in solution is 0.39 m. if the ph of the solution at equilibrium is 0.76, what is the percent ionization of the acid?

Answer 1

The percent ionization of the acid is 44.56%

How can we calculate the percent ionization of the acid?

To calculate the percent ionization of the acid we are using the formula,

The H⁺ ion concentration [H⁺] = C x,

where, we are given,

C= concentration of the acid.

=0.39 M

x= degree of dissociation of the acid.

And one more thing we are given that, the pH of the acid=0.76.

So from the above statement we can say that,

pH = - log [H⁺]

Or,0.76 = -log [H⁺]

Or, log [H⁺] = -0.76

Or, [H⁺] = antilog -0.76

Or,[H⁺]= 10^-0.76

Or,[H⁺]=0.1738.

Now from the above calculation we know, the H⁺ ion concentration= 0.1738 M.

Now we put the known values in the above equation,

[H+]= Cx

Or,0.1739= 0.39 x

Or, x= 0.4459

From the above calculation we can conclude that the percent Ionization of the acid= 0.4459 X 100= 44.59%≈45%

Learn more about Ionization:

brainly.com/question/1445179

#SPJ4