Answer:
Explanation:
Given
balloon is ascending at the rate of
Balloon is at a height of
As the package is dropped from the balloon it must possess the same initial velocity as the balloon
using
where v=final velocity
u=initial velocity
a=acceleration
s=displacement
time taken is given by
substituting values
as we consider downward direction as positive
therefore time taken to reach the bottom is t=5.44 s
Answer:
k = 45.95 N/m
Explanation:
First, we will find the launch speed of the ball by using the formula for the horizontal range of the projectile.
where,
Vo = Launch Speed = ?
R = Horizontal Range = 5.3 m
θ = Launch Angle = 35°
Therefore,
v₀² = 55.33 m²/s²
Now, we know that the kinetic energy gain of ball is equal to the potential energy stored by spring:
where,
k = spring constant = ?
x = compression = 17 cm = 0.17 m
m = mass of ball = 24 g = 0.024 kg
Therefore,
<u>k = 45.95 N/m</u>