Question

A projectile is fired from ground level with an initial speed of 650 m/sec and an angle of elevation of 30 degrees. Use that the acceleration due to gravity is 9.8 m/sec2m/sec2. (a) The range of the projectile is meters. (b) The maximum height of the projectile is meters. (c) The speed with which the projectile hits the ground is 650 m/sec.

Answer 1

Answer:

(a) The range of the projectile is 37,336.3 m

(b) The maximum height of the projectile is 5,389.03 m

Explanation:

Given;

initial velocity of the projectile, u = 650 m/s

angle of projection, θ = 30⁰

(a) The range of the projectile is calculated as;

$R = \frac{u^2sin 2\theta}{g} \\\\R = \frac{(650^2)Sin (2\times 30^0)}{9.8} \\\\R = 37,336.3 \ m$

(b) The maximum height of the projectile is calculated as;

$H = \frac{u^2sin^2\theta}{2g} \\\\H = \frac{(650^2)(Sin \ 30^0)^2}{2\times 9.8} \\\\H = \frac{(650^2)(0.5)^2}{19.6} \\\\H = 5,389.03 \ m$