Question

At 25°C, what is the fraction of collisions with energy equal to or greater than an activation energy of 100. kJ/mol?

Answer 1

Here we have to find out at 25°C, what is the fraction of collisions with energy equal to or greater than an activation energy of 100. kJ/mol.

Given:

Temperature = 25° C (273+ 25 = 298 K),

Activation energy (Ea) = 100 kJ/mol

From Arrhenius equation it has been found that the fraction of collisions with a specified energy is equal to the .

f =  - Ea / RT

⇒ f = 2.957 × 10⁻¹⁸

⇒ f = 2.96 × 10⁻¹⁸

Thus the fraction of collision is found to be  2.9610-18 is greater than activation energy.

To learn more about activation energy here

brainly.com/question/28297085

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