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iren [92.7K]
2 years ago
8

2. Do you think the density of the ice affected the melting rate of the ice, or do you think adding the objects affected the mel

ting rates?
Physics
1 answer:
Setler [38]2 years ago
3 0

The density of ice does not affect its melting rate. Adding objects will affect the melting rate.

  • A physical process called melting or fusing causes a substance to change its phase from a solid to a liquid. This happens when the solid's internal energy rises, usually as a result of heat or pressure being applied, which raises the substance's temperature to the melting point.
  • The term "density" refers to an extensive quality, which means that it is independent of the substance's concentration. Every substance in the world demonstrates its distinctive density. Since it does not fluctuate, it would not affect the rate of melting. The addition of the objects could speed up the process, though, as each one generates heat that could act as the mediating force for the melting process.

To learn more about density, visit :

brainly.com/question/15164682

#SPJ9

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Why do earthquakes and volcanoes occur along continent and ocean boundaries?
jeyben [28]
Earths plates move, creating them to rub together to create earthquakes, and volcanoes occur because magma melts rocks and the pressure is so intense it causes the lava to leak out of the top of a mountain

4 0
3 years ago
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Which geologic feature would most likely be represented by contour lines drawn far apart from one another?
Anna [14]
It would most definitely not be a hill or a cliff. I believe it would be a plain.
5 0
3 years ago
The radioactive isotope U-238 has protons and neutrons.
Archy [21]

Answer:

92 protons, 146 neutrons

Explanation:

Uranium will always have the same amount of protons, because that is what defines the element. Uranium has 92 protons, meaning that the rest of the mass of the atom comes from neutrons. 238-92=146 neutrons. Hope this helps!

4 0
3 years ago
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a box is at rest on a ground. An unbalance force acts on the box causes it to start. The box moves 10 meters in 2 seconds and th
nordsb [41]
The box stopped moving because there was a negative acceleration in the x direction caused by friction.
To find the average speed, simply divide the displacement by time: 10 / 2 = 5 m/s
5 0
2 years ago
Two parallel disks of diameter D 5 0.6 m separated by L 5 0.4 m are located directly on top of each other. Both disks are black
oksian1 [2.3K]

To solve this problem it is necessary to apply the concepts related to the Stefan-Boltzmann law which establishes that a black body emits thermal radiation with a total hemispheric emissive power (W / m²) proportional to the fourth power of its temperature.

Heat flow is obtained as follows:

Q = FA\sigma\Delta T^4

Where,

F =View Factor

A = Cross sectional Area

\sigma = Stefan-Boltzmann constant

T= Temperature

Our values are given as

D = 0.6m

L = 0.4m\\T_1 = 450K\\T_2 = 450K\\T_3 = 300K

The view factor between two coaxial parallel disks would be

\frac{L}{r_1} = \frac{0.4}{0.3}= 1.33

\frac{r_2}{L} = \frac{0.3}{0.4} = 0.75

Then the view factor between base to top surface of the cylinder becomes F_{12} = 0.26. From the summation rule

F_{13} = 1-0.26

F_{13} = 0.74

Then the net rate of radiation heat transfer from the disks to the environment is calculated as

\dot{Q_3} = \dot{Q_{13}}+\dot{Q_{23}}

\dot{Q_3} = 2\dot{Q_{13}}

\dot{Q_3} = 2F_{13}A_1 \sigma (T_1^4-T_3^4)

\dot{Q_3} = 2(0.74)(\pi*0.3^2)(5.67*10^{-8})(450^4-300^4)

\dot{Q_3} = 780.76W

Therefore the rate heat radiation is 780.76W

5 0
3 years ago
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