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ExtremeBDS [4]
1 year ago
5

How can an object's motion be described and predicted?

Physics
1 answer:
Luba_88 [7]1 year ago
3 0

Predicted motion is that motion in which the motion of the body or object is been predicted that the motion will be like this.

<h3>How can an object's motion be described and predicted?</h3>

According to the Newton's second law of motion say's that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass. We can use it for the prediction of the motion of an object. The net force is the vector quantity which is the sum of all the forces which are acting upon the object.

So we can conclude that: Predicted motion is that motion in which the motion of the body or object is been predicted that the motion will be like this.

Learn more about Object Motion here: brainly.com/question/7074120

#SPJ1

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Tresset [83]

Which of the following statements is TRUE?

A. Pollen, cat hair, and mold could trigger an asthma attack for some people.

I am fairly certain that this one is correct. Hope this helps! :)

5 0
3 years ago
PLZ HELP
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The definition of speed is (distance covered) / (time to cover the distance) .

So a unit of speed has to be (a unit of length) / (a unit of time) .

Here are several perfectly fine units of speed:

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8 0
3 years ago
A bimetallic strip (brass/steel), which is straight at room temperature, will be immersed in boiling water and allowed to equili
lakkis [162]

The thermal expansion of the materials allows to find the deflection of the bimetallist strip is Δy = 3.48 cm

given paramers

    * Bimetallic brass / steel tape

    * Initial temperature, room temperature T = 20ºC

    * Final temperature, boiling water  = 100ºC

    * initial length L₀ = 222mm (1cm / 10mm) = 22.2cm

    * thickness of bimetallic tape e = 0.036 inch (2.54 cm/1 inch) = 0.0914 cm

to find

    * perpendicular deviation or deflection (Δy)

Thermal expansion is the phenomenon of change in the length of a body due to the change in temperature, due to the increase in the length of the atomic and molecular bonds, macroscopically it is described by

        ΔL = α L₀ ΔT

ΔL and ΔT are the variation of the length and temperature respectively, L₀ is the initial length and α the coefficient of expansion ends.

In this case we have a strip formed by two materials with different coefficient of thermal expansion,

Brass       α_{brass}   = 19 10⁻⁶ ºC⁻¹

Steel       α_{steel}    = 11 10⁻⁶ ºC⁻¹

In the attached we can see a diagram of the process, as the temperature increases, the material with greater thermal expansion lengthens more, so the system must curve towards the center of the material with less

thermal expansion. Let's find the length of the strip for each material

brass          L_{f brass} - L₀ = α_{brass} L₀ ΔT

Steel           L_{f steel} - L₀ = \alpha_{steel} L₀ ΔT

Note that the initial length is the same for the two materials and that the strip is in thermal equilibrium at room temperature.

If we assume that we have an arc of circumference, we can write the length of the arc

        θ = L / r

where θ is the angle in radines, L the length of the arc and r the radius of curvature, let's write this equation for each material

brass     L_{f \ brass} =θ r₁

steel      L_{f \ steel} = θ r₂

we substitute in our equations

           θ r₁ - L₀ = α_{brass} L₀ ΔT

           θ r₂ - L₀ = α_{steel} L₀ ΔT

let's subtract the two equations

           θ (r₁- r₂) = L₀ ΔT (α_{brass} - α_{steel})

the thickness of the strip is

           e = r₁ -r₂

           θ = Lo \ \Delta T \ \frac{\alpha_{brass} - \alpha_{steel}}{e}

we calculate

           θ = 22.2 \ (100-20) \ \frac{(19-11) \ 10^{-6}}{0.0914}

           θ = 0.155 rad

Let's use trigonometry to find the perpendicular deflection

          tan θ = Δy / L₀

          Δy = L₀ tan θ

          Δy = 22.2 tan 0.155

          Δy = 3.48 cm

Using the thematic expansion of the two materials we find the deflection of the bimetallist strip is 3.38 cm

Learn more about thermal expansion here: brainly.com/question/18717902

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Answer:

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Rightwards is the positive elicitation:

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