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ExtremeBDS [4]
2 years ago
5

How can an object's motion be described and predicted?

Physics
1 answer:
Luba_88 [7]2 years ago
3 0

Predicted motion is that motion in which the motion of the body or object is been predicted that the motion will be like this.

<h3>How can an object's motion be described and predicted?</h3>

According to the Newton's second law of motion say's that the acceleration of an object is directly proportional to the net force applied to it and inversely proportional to its mass. We can use it for the prediction of the motion of an object. The net force is the vector quantity which is the sum of all the forces which are acting upon the object.

So we can conclude that: Predicted motion is that motion in which the motion of the body or object is been predicted that the motion will be like this.

Learn more about Object Motion here: brainly.com/question/7074120

#SPJ1

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When you approach a light source that in turn is moving towards you, your speed relative to the emitted light waves _____.?
Natalka [10]
This is a trick question:

The Doppler effect states that as you move closer to the source, the frequency of light(or sound/waves in general) increases, but technically the speed of light is always the same speed, even if you are moving at the speed of light.

Thus, the answer would be something along the lines of <u>don't change</u>.
7 0
3 years ago
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2. Another car weighs 2000kg, you can push it .05 m/s?, how much force are you
Vesna [10]

Answer:

\boxed {\boxed {\sf 100 \ Newtons}}

Explanation:

We are asked to calculate the force you are applying to a car. According to Newton's Second Law of Motion, force is the product of mass and acceleration. Therefore, we can use the following formula to calculate force.

F= m \times a

The mass of the car is 2000 kilograms and the acceleration is 0.5 meters per second squared.

  • m= 2000 kg
  • a= 0.05 m/s²

Substitute the values into the formula.

F= 2000 \ kg \times 0.05 \ m/s^2

Multiply.

F= 100 \ kg *m/s^2

Convert the units. 1 kilogram meter per second squared is equal to 1 Newton. Our answer of 100 kilogram meters per second square is equal to 100 Newtons.

F= 100 \ N

You apply <u>100 Newtons</u> of force to the car.

7 0
3 years ago
What is the pair of vectors if summed , would create of equilibrium (a resultant of 0i + 0j) ?
bogdanovich [222]
<u>ANY</u> pair of vectors can produce that resultant, as long as ...

If one of the vectors is V₁ = A i + B j . . . . . . where 'A' and 'B' are <u>any</u> two numbers,

then the other one is V₂ = -A i - B j


6 0
4 years ago
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A woman is 1.6 m tall and has a mass of 50 kg. She moves past an observer with the direction of the motion parallel to her heigh
eduard

To solve this problem it is necessary to apply the concepts related to linear momentum, velocity and relative distance.

By definition we know that the relative velocity of an object with reference to the Light, is defined by

V_0 = \frac{V}{\sqrt{1-\frac{V^2}{c^2}}}

Where,

V = Speed from relative point

c = Speed of light

On the other hand we have that the linear momentum is defined as

P = mv

Replacing the relative velocity equation here we have to

P = \frac{mV}{\sqrt{1-\frac{V^2}{c^2}}}

P^2 = \frac{m^2V^2}{1-\frac{V^2}{c^2}}

P^2 = \frac{P^2V^2}{c^2}+m^2V^2

P^2 = V^2 (\frac{P^2}{c^2}+m^2)

V^2 = \frac{P^2}{\frac{P^2}{c^2}+m^2}

V^2 = \frac{(2.1*10^10)^2}{\frac{(2.1*10^10)^2}{(3.8*10^8)^2}+50^2}

V = 2.81784*10^8m/s

Therefore the height with respect the observer is

l = l_0*\sqrt{1-\frac{V^2}{c^2}}

l = 1.6*\sqrt{1-\frac{(2.81*10^8)^2}{(3*10^8)^2}}

l = 0.56m

Therefore the height which the observerd measure for her is 0.56m

8 0
3 years ago
How old was Antoine Lavoisier's wife when they married
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jsjshebsjsusunxndj 78

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